they involve tie sharing of 2 electrons pairs.
PbCl₂(aq) → Pb²⁺(aq) + 2Cl⁻(aq)
NaCl(aq) → Na⁺(aq) + Cl⁻(aq)
Pb²⁺(aq) + 2Cl⁻(aq) ⇄ PbCl₂(s)
At increase the concentration of chloride ions - concentration of lead ions decreases, the lead chloride is formed.
Answer:
c. 0.750 atm
.
Explanation:
Hello!
In this case, since the two vessels have different volume, we can see that the gas is initially at 3.00 atm into the 1.00-L vessel, but next, it is allowed to move towards the 3.00-L vessel, meaning that the final volume wherein the gas is located, is 4.00 L; therefore, we use the Boyle's law to compute the final pressure:
Therefore the answer is c. 0.750 atm
.
Best regards!
Answer:
The particles in the neutral paper can shift, causing the paper to become polarized and attracted to the rod.
Explanation:
The neutral paper has an even distribution of its electrons throughout the paper. If a charged rod is brought near the neutral paper, this can cause the electrons in the paper to shift. If the rod is negative, the electrons will be repelled from the rod and cause the molecules in the paper to have a slight positive charge on the part of the paper closest to the rod. If the rod is positive, the electrons will be attracted to the rod and cause a slight negative charge on the side of the paper closest to the rod.
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