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vodomira [7]
3 years ago
14

What is the average rate of change of the function f(x) =2^x from x=0 to x=2?

Mathematics
1 answer:
krek1111 [17]3 years ago
4 0

Answer:

B

Step-by-step explanation:

The average rate of change of f(x) in the close interval [ a, b ] is

\frac{f(b)-f(a)}{b-a}

Here [ a, b ] = [ 0, 2 ]

f(b) = f(2) = 2² = 4

f(a) = f(0) = 2^{0} = 1, thus

average rate of change = \frac{4-1}{2-0} = \frac{3}{2} → B

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