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Sindrei [870]
3 years ago
11

Jeff ran on two different days. The first day he ran 5/6 mile and the second day he 1/3 ran mile. What is the total distance Jef

f ran?
Mathematics
1 answer:
stira [4]3 years ago
5 0
All you have to do is add.

5/6 + 1/3

Change into a common denominator: 6

5/6 is already changed

1 × 2 / 3 × 2 = 2/6

2/6 + 5/6 = 7/6 = 1 1/6

Answer = 1 1/6 miles

Hope this helped :)
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lakkis [162]

Answer: The answer for x is 6.75. The answer for y 6.75.

Step-by-step explanation:

You are going to mutiple 0.75 x 9 = 6.75. Then, mutiple 0.50 x 9= 4.5. Hope this works.

4 0
3 years ago
Read 2 more answers
8/x-5 - 9/x-4 = 5/x^2-9x+20
adelina 88 [10]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2752942

_______________


Solve the equation:

\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}


Reduce the fractions at the left side so that they have the same denominator:

\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}


Numerators must be equal:

\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}


I hope this helps. =)


Tags:  <em>rational equation fraction solution algebra</em>

7 0
3 years ago
Please help I’m struggling
Ivenika [448]

Answer:

ok

Step-by-step explanation:

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3 0
3 years ago
Prove the sum of two rational numbers is rational where a, b, c, and d are integers and b and d cannot be zero. Fill in the miss
mario62 [17]

Answer:

We conclude that the sum of two rational numbers is rational.

Hence, the fraction will be a rational number. i.e.

  • \frac{ad+cb}{bd}       ∵ b≠0, d≠0, so bd≠0

Step-by-step explanation:

Let a, b, c, and d are integers.

Let a/b and c/d are two rational numbers and b≠0, d≠0

Proving that the sum of two rational numbers is rational.

\frac{a}{b}+\frac{c}{d}

As the least common multiplier of b, d: bd

Adjusting fractions based on the LCM

\frac{a}{b}+\frac{c}{d}=\frac{ad}{bd}+\frac{cb}{db}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

          =\frac{ad+cb}{bd}

As b≠0, d≠0, so bd≠0

Therefore, we conclude that the sum of two rational numbers is rational.

Hence, the fraction will be a rational number. i.e.

  • \frac{ad+cb}{bd}       ∵ b≠0, d≠0, so bd≠0
3 0
3 years ago
4A.
antoniya [11.8K]

The number of paychecks Jalen will have to save until he can purchase the laptop is 6

<h3>How many paychecks will Jalen have to save until he can purchase the laptop? </h3>

<u>Define your variable</u>

To do this, we use the following variables

  • x represents the number of paychecks
  • y represents the cost of the laptop

<u>Set up an equation, and solve it.</u>

In (a), we have:

  • x represents the number of paychecks
  • y represents the cost of the laptop

Using the above variables, the equation is:

y = 200 + 50x

The cost of the laptop is $500.

So, we have:

200 + 50x = 500

Evaluate the like terms

50x = 300

Divide by 50

x = 6

Hence, the number of paychecks Jalen will have to save until he can purchase the laptop is 6

Read more about linear equations at:

brainly.com/question/14323743

#SPJ1

4 0
1 year ago
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