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Delvig [45]
2 years ago
14

A bottle and its cork cost $1.20 of the bottle costs $1.10 more than the cork. What is the cost of bottle and of the cost of cor

k?
Mathematics
1 answer:
777dan777 [17]2 years ago
8 0
The cost of the bottle alone costs $1.15, and the cork costs $0.05, you add them together and you get  $1.20. That is how the bottle costs $1.20.
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Determine the correct scientific notation form of the number. 327,000,000,000
I am Lyosha [343]

Answer:

B. 3.27 x 10^11.

Step-by-step explanation:

There are 11 digits after the first one, so it is

3.27 x 10^11.

5 0
2 years ago
We are learning about angle
neonofarm [45]

Answer:

Step-by-step explanation:

If you cut the square apart along a diagonal, you'll then have two isosceles triangles.  Each such triangle will have 3 sides and 3 angles.  

Next time, please type in a more descriptive title for your question.

7 0
3 years ago
Could someone help me, please?
k0ka [10]

We can rewrite the expression under the radical as

\dfrac{81}{16}a^8b^{12}c^{16}=\left(\dfrac32a^2b^3c^4\right)^4

then taking the fourth root, we get

\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|

Why the absolute value? It's for the same reason that

\sqrt{x^2}=|x|

since both (-x)^2 and x^2 return the same number x^2, and |x| captures both possibilities. From here, we have

\left|\dfrac32a^2b^3c^4\right|=\left|\dfrac32\right|\left|a^2\right|\left|b^3\right|\left|c^4\right|

The absolute values disappear on all but the b term because all of \dfrac32, a^2 and c^4 are positive, while b^3 could potentially be negative. So we end up with

\dfrac32a^2\left|b^3\right|c^4=\dfrac32a^2|b|^3c^4

3 0
3 years ago
Examine the system of equations.
MrMuchimi

answer:

x =  - 2 \\ y = 2 \\  \\ ( - 2, \: 2)

explanation:

y =  -  \frac{1}{2} x + 1 \\ y = 2x + 6 \\ first \: equation \: add \:  \frac{1}{2} from \: both  \\  sides \\   \\ second \: equation \: subtract \: 2x \: from  \\  both \: sides \\  \\ y +  \frac{1}{2} x = 1 \\ y - 2x = 6 \\ solve \: the \: first \: equation \\  \\ y +  \frac{1}{2} x = 1 \\ subtract \:  \frac{x}{2} from \: both \: sides \\  \\ y =  -  \frac{1}{2} x + 1 \\ substitute \:  -  \frac{x}{2}  + 1 \: for \: y \: in \: the  \\ other \: equation \\  \\  -  \frac{1}{2} x + 1 - 2x = 6 \\ add \:   \frac{1}{2} x \: to \: 2x \\  \\  -  \frac{5}{2} x + 1 = 6 \\ subtract \: 1 \: from \: both \: sides \\  \\  -  \frac{5}{2} x = 5 \\ divide \: both \: sides \: by \:  -  \frac{5}{2}  \\  \\ x =  - 2 \\ substitute \: the \: value \: of \: x \: into \\ an \: equation \\  \\ y =  -  \frac{1}{2} ( - 2) + 1 \\ distribute \\  \\ y = 1 + 1 \\ add  \\  \\ y = 2 \\  \\ ( - 2, \: 2)

7 0
2 years ago
What is a commutative property of addition mean
vivado [14]
The commutative property of addition means that when you see a problem, you change the order. The co in commutative means change order. That's what my teacher told me.
6 0
3 years ago
Read 2 more answers
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