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Likurg_2 [28]
4 years ago
14

Concentration measurements provide a quantitative measurement of the amount of solute that is dissolved in a given amount of sol

vent. True or false?
Chemistry
1 answer:
dem82 [27]4 years ago
7 0
I am pretty sure it’s true
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What are smart cancer treatments
natita [175]

Is a potential to provide effective treatment with fewer side effects than a traditional therapy.

3 0
4 years ago
True Or False: "the baseball fans are cheering therefore a ball was hit out of the park" is an example of an inference.
GuDViN [60]

Answer:

False

Explanation:

8 0
3 years ago
A mixture containing nitrogen and hydrogen weighs 3.48 g and occupies a volume of 7.47 L at 296 K and 1.02 atm. Calculate the ma
Sonbull [250]

Answer:

there is 2% of hydrogen and 98% of nitrogen (mass percent)

Explanation:

assuming ideal gas behaviour

P*V=n*R*T

n= P*V/(R*T)

where P= pressure=1.02 atm , V=volume=7.47 L , T=absolute temperature= 296 K and R= ideal gas constant = 0.082 atm*L/(mole*K)

thus

n= P*V/(R*T) = 1.02 atm*7.47 L/( 296 K * 0.082 atm*L/(mole*K)) = 0.314 moles

since the number of moles is related with the mass m through the molecular weight M

n=m/M

thus denoting 1 as hydrogen and 2 as nitrogen

m₁+m₂ = mt (total mass)

m₁/M₁+m₂/M₂ = n

dividing one equation by the other and denoting mass fraction w₁= m₁/mt , w₂= m₂/mt , w₂= 1- w₁

w₁/M₁+w₂/M₂ = n/mt

w₁/M₁+(1-w₁) /M₂ = n/mt

w₁*(1/M₁- 1/M₂) + 1/M₂ = n/mt

w₁=  (n/mt- 1/M₂) /(1/M₁- 1/M₂)

replacing values

w₁=  (n/mt- 1/M₂) /(1/M₁- 1/M₂) = (0.314 moles/3.48 g - 1/(14 g/mole)) /(1/(1 g/mole)-1/(14 g/mole))= 0.02 (%)

and w₂= 1-w₁= 0.98 (98%)

thus there is 2% of hydrogen and 98% of nitrogen

4 0
3 years ago
Water from a riverbed carries sediment downstream. The water pressure cuts deep into the riverbed, creating a deep, narrow chann
atroni [7]

Answer:

A canyon has formed.

Explanation:

5 0
3 years ago
To make a 450g solution with a mass by mass concentration of 7%, how much salt and water do you need to mix?​
Yuri [45]

Explanation:

The given data is:

The mass% of a solution is 7.

Mass of solution =450g

The mass of salt required can be calculated as shown below:

mass percent =(mass of solute/mass of solution )x100\\

Substitute the given values in this formula to get the mass of solute that is salt:

mass percent =(mass of solute/mass of solution )x100\\\\7=\frac{mass of salt}{450g} x100\\=>mass of salt=7x450g /100\\mass of salt=31.5g

Mass of salt =31.5g

Mass of solvent that is water = 450g-31.5g=418.5g

4 0
3 years ago
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