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Stella [2.4K]
3 years ago
7

Describe the R group found within an amino acid

Chemistry
1 answer:
madreJ [45]3 years ago
5 0

Hello!

An amino acid has five basic parts. An amino group, a carboxyl group, a central carbon atom, a hydrogen, and a R group.

The r group is the side chain specific to each amino acid. The r group varies between each kind of amino acid, while everything else stays the same. Therefore, the r group decides the identity of the amino acid.

Hope this helps! Let me know if you need a more specific explanation.

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Lakes can disappear due to *
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Answer:

Drought, resulting in a 65% reduction in water levels.

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In what ways do scientists not study the history of Earth's climate?
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(A) Studying ice cores
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Water combines with carbon dioxide Choose one: A. only in the atmosphere. B. to produce hydrogen sulfide. C. to precipitate calc
katovenus [111]

Water combines with carbon dioxide to produce slightly acidic groundwater

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Read more on brainly.com/question/25385913

8 0
3 years ago
A 25.0-mL sample of 0.150 M hydrazoic acid, HN3, is titrated with a 0.150 M NaOH solution. What is the pH after 13.3 mL of base
tamaranim1 [39]

Answer:

pH ≅ 4.80

Explanation:

Given that:

the volume of HN₃ = 25 mL = 0.025 L

Molarity of HN₃ = 0.150 M

number of moles of HN₃ = 0.025 × 0.150

number of moles of HN₃ =  0.00375  mol

Molarity of NaOH = 0.150 M

the volume of NaOH = 13.3 mL = 0.0133

number of moles of NaOH = 0.0133× 0.150

number of moles of NaOH = 0.001995 mol

The chemical equation for the reaction of this process can be written as:

HN_3 + OH- ---> N^-_{3} + H_2O

1 mole of hydrazoic acid react with 1 mole of hydroxide to give nitride ion and water

thus the new number of moles of HN₃ = 0.00375 - 0.001995 = 0.001755 mol

Total volume used in the reaction =  0.025 +  0.0133 = 0.0383  L

Concentration of HN_3 = \dfrac{0.001755}{0.0383} = 0.0458 M

Concentration of N^{-}_3 = \dfrac{ 0.001995 }{0.0383} = 0.0521 M

GIven that :

Ka = 1.9 x 10^{-5}

Thus; it's pKa = 4.72

pH =4.72 +  log(\dfrac{ \ 0.0521}{0.0458})

pH =4.72 + log(1.1376)

pH =4.72 + 0.05598

pH =4.77598

pH ≅ 4.80

3 0
3 years ago
PLEASE HELP ME!!!
irina [24]

that's the answer I think

6 0
2 years ago
Read 2 more answers
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