Answer:
Here's what I get
Explanation:
Ethylamine has an N atom with a lone pair of electrons.
It can act as a Brønsted-Lowry base and accept a proton from water and become an ethylammonium ion.
The structure of the ion is shown below (there is a C atom at each of the four-way bond intersections).
Energy E = hc / l
where h = Planck's constant, c = speed of light and l = wavelength.
E = 1.986 * 10^-25 / 3.8 * 10^-7 = 5.223*10^-19
C is the answer to the problem
Answer:
Al + MnO4- + 2H2O → Al(OH)4- + MnO2
Explanation:
First of all, we out down the skeleton equation;
Al + MnO4- → MnO2 + Al(OH)4-
Secondly, we write the oxidation and reduction equation in basic medium;
Oxidation half equation:Al + 4H2O + 4OH- → Al(OH)4- + 4H2O + 3e-
Reduction half equation:MnO4- + 4H2O + 3e- → MnO2 + 2H2O + 4OH-
Thirdly, we add the two half reactions together to obtain:
Al + MnO4- + 8H2O + 4OH- + 3e- → Al(OH)4- + MnO2 + 6H2O + 3e- + 4OH-
Lastly, cancel out species that occur on both sides of the reaction equation;
Al + MnO4- + 8H2O→ Al(OH)4- + MnO2 + 6H2O
The simplified equation now becomes;
Al + MnO4- + 2H2O → Al(OH)4- + MnO2
Answer:
4,1,4
Explanation:
Balancing a synthesis equation
