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vekshin1
2 years ago
12

Near Tatooine's famous Mos Eisley Space port you found a 774.92 mL block of gold. What is the mass in kilograms of this block? H

ELp me please!! I need to turn this in soon
(1000 g = 1 kg, 2.2 lbs = 1 kg)

Metal Density (g/cm3)
Aluminum 2.7
Zinc 7.1
Copper 9.0
Silver 10.5
Lead 11.4
Gold 19.3
Chemistry
1 answer:
natima [27]2 years ago
8 0
774.92 ml = 0.77492 L =0.77492 cm3
Gold density =19.3 = x/0.77492 => x=14.96 g = 0.01496 Kg
Can u mark it brainliest if my answer is correct?
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Help please asap. chem sucks
luda_lava [24]

I'm assuming that C is carbon.

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2 years ago
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zmey [24]

Answer:

0.125. work- divide the volume value by 1000

873. work- multiply the length value by 100

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1) Centigram = Kilogram * 100000

2) Centigram = 0.981 * 100000

3) Centigram = 98100

285.65. work- 12.5°C + 273.15 = 285.65K

446.85. work- 720K − 273.15 = 446.85°C

346.25. work- 73.1°C + 273.15 = 346.25K

Explanation:

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8 0
3 years ago
Describe the difference between accuracy and precision. How do these two concepts relate to the idea of significant digits?
Soloha48 [4]

Answer:

Accuracy of a measured value refers to how close a measurement is to the correct value. The uncertainty in a measurement is an estimate of the amount by which the measurement result may differ from this value. Precision of measured values refers to how close the agreement is between repeated measurements.

Explanation:

3 0
2 years ago
A solution of sulfuric acid has a concentration of 0.0980 g/L. If the density of the acid is 1.84 g/mL, what is the concentratio
mariarad [96]
The answer is 98ppm.

The ppm (Parts per million) is also a concentration unit. 1 ppm is equivalent to 1mg/L
Now, concentration of the solution of sulfuric acid is 0.0980 g/L.
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6 0
3 years ago
Read 2 more answers
A hypothetical metal crystallizes with the face-centered cubic unit cell. The radius of the metal atom is 234 picometers and its
AleksAgata [21]

Answer:

\delta=101.13 g/cm^3

Explanation:

As can be seen in the Figure in a face-centered cubic unit cell you have:

  • Six halves of atoms
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In total:

n_{atom}=6*0.5+8*\frac{1}{8}=4 atoms

Now, each side of the cell is 234 picometers (2.34e-8 cm) long

V_{cell}=L^3=(2.34e^{-8} cm)^3

V_{cell}=1.28*10^{-23}cm^3

Atoms per cm3:

n=\frac{4 atoms}{1.28*10^{-23}cm^3}

n=3.12*10^{23} atoms/cm^3

Expressing in mass:

\delta=3.12*10^{23} atoms/cm^3* \frac{1 mol}{6.022*10^{23}}*195.08 g/mol

\delta=101.13 g/cm^3

6 0
3 years ago
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