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IrinaVladis [17]
3 years ago
13

How does cellphoe service compare between different cities? table 3 represent the rating of verizon and at&t in 22 different

cities?
Physics
1 answer:
Alex Ar [27]3 years ago
4 0
<span>Cell phone services can be compared through several characteristic. The rate of the data transfer: the higher the rate the better the service, the availability- the percent of the time the service is available (the greater the percent the better the service) and the reliability, which means that the service is non interrupted.</span>



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The eyes of many older people have lost the ability to accommodate, and so an older person’s near point may be more than 25 cm f
tensa zangetsu [6.8K]

Answer:

Smaller refractive power

Explanation:

The refractive power of an eye is the extent to which it can converge or diverge the light rays.

Near point is the the closest point for an eye such that when an object is placed at that point the image it forms is sharp and clearly visible to the eye.

A the person ages, the ciliary muscles of the eyes weakens and as a result the lens contracts and the formation of the image takes place behind the retina instead of forming at the retina.

Thus the near point also increases and the refractive power becomes smaller.

4 0
3 years ago
)) What do these two changes have in common?
zloy xaker [14]

Answer:

Both are only physical changes

Explanation:

A physical change is a change that does not involve or alter the chemical composition of the substances involved. Physical changes form no new substance and can be easily separated into individual constituents. Example of physical changes are change in state, boiling, melting etc.

According to this question, two processes were given as follows:

1. mixing chocolate syrup into milk

2. rain forming in a cloud

These two processes are similar in the sense that they are both examples of physical changes.

7 0
3 years ago
Suppose you want to make an interferometer with two slits to show the wave nature of light to your friends. The most convenient
nevsk [136]

Answer:

a) the pattern is bright,  b)  y = 8.25 mm, c) the distance increases with the wavelength increases

Explanation:

This is a team building exercise to perform interference experiments, where the separation of the slits is d = 1 m = 1 10⁻³ m and the distance to the screen L = 1.5 m  

Constructive interference occurs when the path difference is equal to an integer number of wavelengths  

             d sin θ = m λ  

a) The center of the two-ray pattern has the same length so the intensity is MAXIMUM, that is, the pattern is bright  

b) to find the distance let's use trigonometry  

   tan θ= y / L  

   tan θ =sin θ/cos θ= sin θ  

because the angles are small  

we substitute  

     y = \frac{m \lambda L}{d} 

let's calculate  

     y = 10 550 10⁻⁹ 1.5 / 1 10⁻³  

     y = 8.25 10⁻³ m

c) for this part the incident light must be white or polychrome light  

let's find the distance (y) for some colors, in the first order  

Violet λ = 400  

y = 1 400 10⁻⁹ 1.5 / 1 10⁻³  

y = 6 10⁻⁴ m  

green λ = 500 nm  

y = 1 500 10⁻⁹ 1.5 / 1 10⁻³  

y = 7.5 10⁻⁴ m  

yellow λ = 600 nm  

y = 1 600 10⁻⁹ 1.5 / 1.10⁻³  

y = 9 10⁻⁴ m  

lam λ = 700 nm  

y = 1 700 10⁻⁹ 1.5 / 1. 10⁻³  

y = 1.05 10⁻³ m  

violet, green, orange, red  

the distance increases with the wavelength increases

d) To find the wavelength we must measure the distance y from the center of the slit for various interference orders and using the equation we can find the wavelength of rationality

4 0
3 years ago
Four identical particles of mass 0.980 kg each are placed at the vertices of a 4.14 m x 4.14 m square and held there by four mas
Zielflug [23.3K]

Answer:

a) The rotational inertia when it passes through the midpoints of opposite sides and lies in the plane of the square is 16.8 kg m²

b) I = 50.39 kg m²

c) I = 16.8 kg m²

Explanation:

a) Given data:

m = 0.98 kg

a = 4.14 * 4.14

The moment of inertia is:

I=mr^{2} \\r=\frac{a}{2} \\I=m(a/2)^{2} \\I=\frac{ma^{2} }{4}

For 4 particles:

I=4(\frac{ma^{2} }{4} )=ma^{2} =0.98*(4.14)^{2} =16.8kgm^{2}

b) Distance from top left mass = x = a/2

Distance from bottom left mass = x = a/2

Distance from top right mass = x = √5 (a/2)

The total moment of inertia is:

I=m(\frac{a}{2} )^{2} +m(\frac{a}{2} )^{2}+m(\frac{\sqrt{5a} }{2} )^{2}+m(\frac{\sqrt{5a} }{2} )^{2}=\frac{12ma^{2} }{4} =3ma^{2} =3*0.98*(4.14)^{2} =50.39kgm^{2}

c)

I=2m(\frac{m}{\sqrt{2} } )^{2} =ma^{2} =0.98*(4.14)^{2} =16.8kgm^{2}

8 0
3 years ago
Which of the following statements are true?Check all that apply.
MaRussiya [10]

Answer:

1.The Sun is located at one of the foci of the planets' elliptical orbits.

2.The path of the planets around the Sun is elliptical in shape.

Explanation:

As per Kepler's law of planet motion we know that all planets revolve around the sun in elliptical path in such a way that position of Sun must be at one of the focii of the path

So all planets are in elliptical path always

Position of sun is always at one of the focus

so correct answer will be

1.The Sun is located at one of the foci of the planets' elliptical orbits.

2.The path of the planets around the Sun is elliptical in shape.

4 0
3 years ago
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