Explanation:
may I ask what it is on because I might be able to help out
Assume it is in uniform deceleration.
u=25
v=0
s=x
a=?
t=12
v=u+at
0=25+a(12)
a=-2.08(3sig fig)
decelerarion of 2.08 ms^(-2)/
acceleration=-2.08ms^(-2)
Answer:
-107 m
Explanation:
Sum of forces in the y direction:
∑F = ma
-qE = ma
a = -qE/m
a = -(1.60×10⁻¹⁹ C) (304 N/C) / (9.11×10⁻³¹ kg)
a = -53.4×10¹² m/s²
Given in the y direction:
v₀ = 0 m/s
a = -53.4×10¹² m/s²
t = 2×10⁻⁶ s
Find: Δy
Δy = v₀ t + ½ at²
Δy = (0 m/s) (2×10⁻⁶ s) + ½ (-53.4×10¹² m/s²) (2×10⁻⁶ s)²
Δy = -107 m
I don’t know the first one but the second one is light and the third one is a satellite