Who would you go about this.

Mathematics

1 answer:

Nostrana [21]2 years ago

6 0

A. First move all to the left side of the equation(Normal form)

x^3 - 49x= 0

B. Factor out an x, which is the GCF (Factored form)

x(x^2 - 49) = 0

C. Find solutions by making each x piece equal to 0. The first part is just x=0 and the second part is just factoring the difference of squares and then solving.

x=0, x^2 - 49 =0

x=0, x + 7 = 0, x - 7 = 0

Therefore, the answers for Part C are:
x = 0, x = -7, x = 7

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You go to an arcade and purchase a card with game credits. After playing 5 games you have 33 credits left. You play 4 more games

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Answer:

$y=-3x+48$

Step-by-step explanation:

We will use slope-intercept form of equation to write our equation. The equation of a line in slope-intercept form is: $y=mx+b$ , where m= Slope of the line, b= y-intercept.

To write the equation that represents the number of credits y on the cards after x games, we will find slope of our line.

We have been given that after playing 5 games we have 33 credits left. We play 4 more games and we have 21 credits left. So our points will be (5,33) and (9,21).

Let us substitute coordinates of our both given points in slope formula: $m=\frac{y_2-y_1}{x_2-x_1}$ ,