3 years ago

Who would you go about this.

1 answer:

6 0

A. First move all to the left side of the equation(Normal form)

x^3 - 49x= 0

B. Factor out an x, which is the GCF (Factored form)

x(x^2 - 49) = 0

C. Find solutions by making each x piece equal to 0. The first part is just x=0 and the second part is just factoring the difference of squares and then solving.

x=0, x^2 - 49 =0

x=0, x + 7 = 0, x - 7 = 0

Therefore, the answers for Part C are:
x = 0, x = -7, x = 7

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