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kolbaska11 [484]
2 years ago
10

Triangle ABC is congruent to triangle A′′B′′C′′ . Which sequence of transformations could have been used to transform triangle A

BC to produce ​ triangle A′′B′′C′′ ​ ? ​ Triangle ABC ​ was reflected across the y-axis and then translated 7 units down. ​ Triangle ABC ​ was translated 10 units right and then reflected across the x-axis. ​ Triangle ABC ​ was reflected across the x-axis and then translated 9 units right. ​ Triangle ABC ​ was translated 7 units down and then 9 units right. A coordinate graph with triangle A B C and triangle A double prime B double prime and C double prime. Triangle A B C has points at A begin ordered pair negative 6 comma 2 end ordered pair, B begin ordered pair negative 3 comma 6 end ordered pair, C begin ordered pair negative 3 comma 2 end ordered pair. Triangle A double prime B double prime C double prime has points at A double prime begin ordered pair 6 comma negative 5 end ordered pair, B double prime begin ordered pair 3 comma negative 1 end ordered pair, C double prime begin ordered pair 3 comma negative 5 end ordered pair.
Mathematics
1 answer:
I am Lyosha [343]2 years ago
6 0

Answer:

you must provide the image

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The ratio between the square of a number and it's cube is 1:3 what is the number ​
Dimas [21]

Answer:

3

Step-by-step explanation:

Call that number “x”

The square of that number is x^2

Also as the cube is x^3

The ratio between these 2 values is 1:3, this means x^2 / x^3 = 1 / 3

<==> 1 / x = 1 / 3 (eliminate “x^2” for numerator and denominator of the fraction x^2 / x^3 )

<==> x = 1 * 3 / 1 = 3

So, that number is 3 ! This math problem seems simple ;)

4 0
3 years ago
-7 1/3 &gt; -11 1/4 <br> true or false?!?
Varvara68 [4.7K]

Answer:

False

Step-by-step explanation:

8 0
4 years ago
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How do you solve this? cosθ-tanθcosθ=0
laila [671]
First, lets note that tan(\theta)\cdot cos(\theta)=sin(\theta). This leads us with the following problem:

cos(\theta)-sin(\theta)=0

Lets add sin on both sides, and we get:

cos(\theta)=sin(\theta)

Now if we divide with sin on both sides we get:

\frac{cos(\theta)}{sin(\theta)}=1

Now we can remember how cot is defined, it is (cos/sin). So we have:

cot(\theta)=1

Now take the inverse of cot and we get:
\theta=cot^{-1}(1)=\pi\cdot n+ \frac{\pi}{4} , \quad n\in \mathbb{Z}

In general we have cot^{-1}(1)=\frac{\pi}{4}, the reason we have to add pi times n, is because it is a function that has multiple answers, see the picture:

4 0
3 years ago
PIC BELOW <br> Need answer ASAP
MArishka [77]

Option D. 17/10 or 1.7 is correct or 1 7/10 is also correct :)

8 0
3 years ago
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What is the shape of the cross section taken parallel to the base of a cylinder? circle rectangle triangle ellipse
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The option A is correct. A circle is the shape of the cross section taken parallel to the base of a cylinder.

According to the statement

We have given that the cylinder and we have to tell that the which shape required for the cross section taken parallel to the base of a cylinder.

So, For this purpose,

We know that the

A cylinder is a three-dimensional solid, one of the most basic geometric shapes.

In this shape the surface formed by the points at a fixed distance from a  line segment, which is  known as the axis of the cylinder.

As the bases of cylinder are two identical circles which are parallel to the curved surface.

The curved surface when we open will be circle rather than the circle.

So, Due to this reason the answer is a circle.

Therefore, a circle is the shape of the cross section taken parallel to the base of a cylinder.

Learn more about base of cylinder here

brainly.com/question/76387

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