Answer:
6813.7g
Explanation:
Calculate the mass
Let x be the mass
If 1 mol of Fe has a mass of 55.85 g
1 mol =55.85g
122mol= x
we have x= 122•55.85g=6813.7g
There is 0.02538502095915 Moles in 5 grams of gold.
Answer:
35.8 g
Explanation:
Step 1: Given data
Mass of water: 63.5 g
Step 2: Calculate how many grams of KCl can be dissolved in 63.5. g of water at 80 °C
Solubility is the maximum amount of solute that can be dissolved in 100 g of solute at a specified temperature. The solubility of KCl at 80 °C is 56.3 g%g, that is, we can dissolve up to 56.3 g of KCl in 100 g of water.
63.5 g Water × 56.3 g KCl/100 g Water = 35.8 g KCl