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Fynjy0 [20]
3 years ago
12

A 4 liter solution of bleach with a concentration of 0.5 moles/L is diluted using an extra 4 Liters of water. What is the final

concentration of the solution?
Chemistry
1 answer:
blondinia [14]3 years ago
3 0

Answer:

0.25 mol/L

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 4L

Initial concentration (C1) = 0.5 mol/L

Final volume (V2) = 4 + 4 = 8L

Final concentration (C2) =?

Applying the dilution formula, we can easily find the concentration of the diluted solution as follow:

C1V1 = C2V2

0.5 x 4 = C2 x 8

Divide both side by 8

C2 = (0.5 x 4 )/ 8

C2 = 0.25 mol/L

Therefore the concentration of the diluted solution is 0.25 mol/L

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I think the answer is chemical change
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A 2.0 L container of nitrogen gas had a pressure of 3.2 atm. What volume would be necessary to decrease the pressure to 1.0 atm
beks73 [17]

Answer:

6.4 L

Explanation:

When all other variables are held constant, you can use Boyle's Law to find the missing volume:

P₁V₁ = P₂V₂

In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the theoretical volume by plugging the given values into the equation and simplifying.

P₁ = 3.2 atm                      P₂ = 1.0 atm

V₁ = 2.0 L                          V₂ = ? L

P₁V₁ = P₂V₂                                                    <----- Boyle's Law

(3.2 atm)(2.0 L) = (1.0 atm)V₂                        <----- Insert values

6.4 = (1.0 atm)V₂                                           <----- Simplify left side

6.4 = V₂                                                        <----- Divide both sides by 1.0

6 0
2 years ago
What is the orbital hybridization of a central atom that has one lone pair and bonds to:
svlad2 [7]

sp^3d is the type of orbital hybridization of a central atom that has one lone pair and bonds to four other atoms.

<h3>What is orbital hybridization?</h3>

In the context of valence bond theory, orbital hybridization (or hybridisation) refers to the idea of combining atomic orbitals to create new hybrid orbitals (with energies, forms, etc., distinct from the component atomic orbitals) suited for the pairing of electrons to form chemical bonds.

For instance, the valence-shell s orbital joins with three valence-shell p orbitals to generate four equivalent sp3 mixes that are arranged in a tetrahedral configuration around the carbon atom to connect to four distinct atoms.

Hybrid orbitals are symmetrically arranged in space and are helpful in the explanation of molecular geometry and atomic bonding characteristics. Usually, atomic orbitals with similar energies are combined to form hybrid orbitals.

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brainly.com/question/22765530

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5 0
2 years ago
The nucleus of isotope A of an element has a larger mass than isotope B of the same elemen
konstantin123 [22]

Answer:

B

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since isotopeA has bigger mass number

7 0
3 years ago
The The thermal conductivity of a sheet of rigid, extruded insulation is reported to be k=0.029 W/ m measured temperature differ
vfiekz [6]

Answer:

Heat flux = 13.92 W/m2

Rate of heat transfer throug the 3m x 3m sheet = 125.28 W

The thermal resistance of the 3x3m sheet is 0.0958 K/W

Explanation:

The rate of heat transfer through a 3m x 3m sheet of insulation can be calculated as:

q=-k*A*\frac{\Delta T}{\Delta X}\\\\q=-0.029\frac{W}{m*K}*(3m*3m)*\frac{12K}{0.025m}  =125.28W

The heat flux can be defined as the amount of heat flow by unit of area.

Using the previous calculation, we can estimate the heat flux:

heat \, flux=\frac{q}{A}=\frac{125.28 W}{9 m^{2} }  =13.92 W/m^{2}

It can also be calculated as:

q/A=-k*\frac{\Delta T}{\Delta X}

The thermal resistance can be expressed as

\Delta T=R_t*Q\\R_t=\Delta T/Q=\frac{\Delta X}{k*A}

For the 3m x 3m sheet, the thermal resistance is

R_t = \frac{\Delta X}{k*A}=\frac{0.025m}{0.029W/mK*9m^{2}}=0.0958 \, K/W

4 0
3 years ago
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