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Fynjy0 [20]
3 years ago
12

A 4 liter solution of bleach with a concentration of 0.5 moles/L is diluted using an extra 4 Liters of water. What is the final

concentration of the solution?
Chemistry
1 answer:
blondinia [14]3 years ago
3 0

Answer:

0.25 mol/L

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 4L

Initial concentration (C1) = 0.5 mol/L

Final volume (V2) = 4 + 4 = 8L

Final concentration (C2) =?

Applying the dilution formula, we can easily find the concentration of the diluted solution as follow:

C1V1 = C2V2

0.5 x 4 = C2 x 8

Divide both side by 8

C2 = (0.5 x 4 )/ 8

C2 = 0.25 mol/L

Therefore the concentration of the diluted solution is 0.25 mol/L

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How many grams of CO are produced when 41.0 g of C reacts?
CaHeK987 [17]

Answer:

95.7 g CO to the nearest tenth.

Explanation:

2C + O2 ---> 2CO

Using relative atomic masses:

24 g C produces  2*12 + 2*16 g CO.

So 41 g produces  ( (2*12 + 2*16) * 41  ) / 24

= 95.7 g CO,

7 0
2 years ago
How many atoms are there in 3.559*10^-6 mol of krypton?
algol [13]

Answer:

The answer is

<h2>2.143 \times  {10}^{18}  \:  \: atoms</h2>

Explanation:

To find the number of atoms given the number of moles we use the formula

N = n × L

where

N is the number of entities

n is the number of moles

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

n = 3.559 \times  {10}^{ - 6}  \: mol

Substitute the values into the above formula and solve

That's

<h3>N  = 3.559 \times  {10}^{ - 6}  \times 6.02 \times  {10}^{23}  \\  = 2.1425 \times  {10}^{18}</h3>

We have the final answer as

<h3>N  = 2.143 \times  {10}^{18}  \:  \: atoms</h3>

Hope this helps you

3 0
3 years ago
If the density of mercury is 13.6 g/mL, what is the mass of 25.4 cm3 of<br> mercury?
Anettt [7]

Answer:

345.44 g or 0.34544 kg

Explanation:

Applying

D = m/V...................... Equation 1

Where D = Density of mercury, m = mass of mercury, V = Volume of mercury.

make m the subject of the equation

m = D×V................. Equation 2

From the question,

Given: D = 13.6 g/mL = 13.6 g/cm³, V = 25.4 cm³

Substitute these values into equation 2

m = 13.6×25.4

m = 345.44 g

m = 0.34544 kg

Hence the mass of mercury is 345.44 g or 0.34544 kg

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2 years ago
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Explanation:

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B. a bike braking

Explanation:

It involves friction! Hope this helps!

8 0
3 years ago
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