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3 years ago

Which of the following has the greatest entropy? (Assume the same number of particles in each sample.)

Physics

2 answers:

vovangra [49]3 years ago

5 0

I believe the answer is steam, because it has the highest temperature.

strojnjashka [21]3 years ago

4 0

<span>Which of the following has the greatest entropy? (Assume the same number of particles in each sample.)
An Ice Cube i think</span>

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Question 7 (2 points)

Arlecino [84]

Answer:

Tire

Explanation:

3 0

3 years ago

A hollow steel ball weighing 4 pounds is suspended from a spring. This stretches the spring 17 feet. The ball is started in moti

Romashka-Z-Leto [24]

twelve because it is the answer

5 0

3 years ago

Read 2 more answers

43 kg bear slides, from rest, 15 m down a lodgepole pine tree, moving with a speed of 5.5 m/s just before hitting the ground. (a

olga2289 [7]

Answer:

-6327.45 Joules

650.375 Joules

378.47166 N

Explanation:

h = Height the bear slides from = 15 m

m = Mass of bear = 43 kg

g = Acceleration due to gravity = 9.81 m/s²

v = Velocity of bear = 5.5 m/s

f = Frictional force

Potential energy is given by

$P=mgh\\\Rightarrow P=43\times -9.81\times 15\\\Rightarrow P=-6327.45\ J$

Change that occurs in the gravitational potential energy of the bear-Earth system during the slide is -6327.45 Joules

Kinetic energy is given by

$K=\frac{1}{2}mv^2\\\Rightarrow K=\frac{1}{2}\times 43\times 5.5^2\\\Rightarrow K=650.375\ J$

Kinetic energy of the bear just before hitting the ground is 650.375 Joules

Change in total energy is given by

$\Delta E=fh=-(\Delta K+\Delta P)\\\Rightarrow fh=-(650.375-6327.45)\\\Rightarrow fh=5677.075\\\Rightarrow f=\frac{5677.075}{h}\\\Rightarrow f=\frac{5677.075}{15}\\\Rightarrow f=378.47166\ N$

The frictional force that acts on the sliding bear is 378.47166 N

5 0

3 years ago

Read 2 more answers

Mimas, a moon of Saturn, has an orbital radius of 1.62 × 108 m and an orbital period of about 23.21 h. Use Newton’s version of K

Drupady [299]

Answer:

$3.60432\times 10^{26}\ kg$

Explanation:

a = Orbital radius = $1.62\times 10^8\ m$

T = Orbital period = 23.21 hours

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

From Kepler's third law we get

$M=\frac{4\pi^2a^3}{GT^2}\\\Rightarrow M=\frac{4\pi^2\times (1.62\times 10^8)^3}{6.67\times 10^{-11}\times (23.21\times 3600)^2}\\\Rightarrow M=3.60432\times 10^{26}\ kg$

From the given data the mass of Saturn is $3.60432\times 10^{26}\ kg$

8 0

3 years ago

A typical circular saw has a radius of 0. 184 m and rotates so the velocity of its edge is 110 m/s. How many RPM does the saw ma

olga_2 [115]

Answer:

[5710 RPM]

Explanation:

5 0

2 years ago