Answer:

Explanation:
initial velocity
magnitude of velocity, v = 12 m/s
angle made of velocity with negative x-axis,θ = 60°
We need to calculate x- component of v

velocity is in negative x-direction, v = -12 m/s
now,



Hence, the velocity x-component is equal to -6 m/s.
Answer:
In order to determine if the cathode ray consisted of charged particles, Thomson used magnets and charged plates to deflect the cathode ray. He observed that cathode rays were deflected by a magnetic field in the same manner as a wire carrying an electric current, which was known to be negatively charged.
Explanation:
Answer:α = 1.00 rad/s², τ = 90.0 N•m, KEr = 1.12 kJ
Explanation:
m = 795/9.81 = 81.0 kg
ω₁ = 47.79 rev/min(2π rad/rev) / (60 s/min) = 5.00 rad/s
α = (ω₁ - ω₀)/τ = (5.00 - 0.00)/5.00 = 1.00 rad/s²
I = ½mR² = ½(81.0)(1.49²) = 90.0 kg•m²
τ = Iα = 90.0(1.00) = 90.0 N•m
KEr = ½Iω² = ½(90.0)5.00² = 1,124.477 ≈ 1.12 kJ
To develop this problem it is necessary to apply the concepts related to the uni-axial deflection of bodies.
From the expression of Hooke's law we have to

Where,
E= Young's modulus
The strain
And substituting P/A for stress and
for strain gives that

Where,
P = Force
A = Area
L = Length
Therefore this can be re-arranged to give

If we want to calculate the deformation per unit area then we can also rewrite the equation as

Replacing with our values we have to


Therefore the posion ratio would be



Therefore the Poisson's ratio for this material is 0.4238