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Alisiya [41]
2 years ago
10

What is the density (in kg/m3) of a woman who floats in freshwater with 4.92% of her volume above the surface

Physics
1 answer:
kipiarov [429]2 years ago
4 0

Answer:

The density of the woman is 950.8 kg/m³

Explanation:

Given;

fraction of the woman's volume above the surface = 4.92%

then, fraction of the woman's volume below the surface = 100 - 4.92% = 95.08%

the specific gravity of the woman = \frac{95.08}{100 } = 0.9508

The density of the woman is calculate as;

Specific \ gravity \ of \ the \ woman = \frac{Density \ of \ the \ woman }{Density \ of \ fresh \ water }\\\\ Density \ of \ the \ woman  = Specific \ gravity \ of \ the \ woman \ \times \ Density \ of \ fresh \ water

Density of fresh water = 1000 kg/m³

Density of the woman = 0.9508 x 1000 kg/m³

Density of the woman = 950.8 kg/m³

Therefore, the density of the woman is 950.8 kg/m³

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shepuryov [24]

La masa molar de 65 litros de SO2 es igual a 64,1 g/mol.

<h3>Masa molar</h3>

La masa molar de un compuesto depende de su masa presente en 1 mol, entonces:

                                          MM=\frac{m}{mol}

Para calcular la masa molar de un compuesto, simplemente suma las masas de cada elemento en el compuesto, así:

MM_O = 16g/mol\\MM_S= 32.1g/mol

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Obtenga más información sobre la masa molar en: brainly.com/question/17109809

8 0
2 years ago
A man 2 m tall walks horizontally at a constant rate of 1 m/s toward the base of a tower 23 m tall. When the man is 10 m from th
Evgen [1.6K]

Answer:

\dfrac{d\theta}{dt}=0.038\ rad/s

Explanation:

Given that

\dfrac{dx}{dt}= -1\ m/s

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tan\theta=\dfrac{21}{x}

By differentiating with time t

sec^2\theta \dfrac{d\theta}{dt}=-\dfrac{21}{x^2}\dfrac{dx}{dt}

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tan\theta=\dfrac{21}{10}

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sec^2\theta \dfrac{d\theta}{dt}=-\dfrac{21}{x^2}\dfrac{dx}{dt}

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\dfrac{d\theta}{dt}=0.038\ rad/s

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3 years ago
A pin fin of uniform, cross-sectional area is fabricated of an aluminum alloy (k = 160 W/m-K). The fin diameter is D = 4 mm, and
frozen [14]

Answer:

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D= 4 mm

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ηf = 0.65

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5 0
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