1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lerok [7]
3 years ago
5

Which of the following functions is graphed below?

Mathematics
1 answer:
Zina [86]3 years ago
6 0

Answer:

B

Step-by-step explanation:

there's no point on x^2 +3 at 4 so x < 4 making it B

You might be interested in
I don't understand how to do this, could I have some help?​
kondaur [170]

Step-by-step explanation:

step 1. slope = rise/run

step 2. the rise is the height between any 2 points

step 3. the run is the distance left or right between the same 2 points

step 4. if the line goes up "left to right" the slope is positive, down it is negative

step 5. slope = + 6/2 = 3.

5 0
3 years ago
The cylinder is 10 meters wide and the volume is 300 cubic meters what's the height of the cylinder?
daser333 [38]
Cylinder is 10 meters wide, so its diameter is 10 meters. You get radius of it by dividing 10 by 2, which equals 5.
As you count volume of cylinder from that equation
V=A*h= \pi  r^{2}*h 
You get an equation to count height:
h= \frac{V}{ \pi  r^{2} } 
h≈3.82 meters
4 0
4 years ago
What is the vertex for this function? y=2x2−12x+16
Scrat [10]

Answer:

(3,-2)

Step-by-step explanation:

Rewrite in vertex form and use this form to find the vertex

4 0
3 years ago
Part 1 state the domain and range of the given relation.
hram777 [196]
A relation is any set of ordered pairs, which can be thought of as (input, output).

A function is a relation in which NO two ordered pairs have the same first component and different second components.

The set of first components (x-coordinates) in the ordered pairs is the DOMAIN of the relation.

The set of second components (y-coordinates) is the RANGE of the relation.

Part 1:
Domain: {-1, 1, 3, 6}
Range: {2, 2, 2, 2}

Part 2:
To determine whether the given relation represents a function, look at the given relation and ask yourself, “Does every first element (or input) correspond with EXACTLY ONE second element (or output)?”

Remember that a function can only take on 1 output for each input.

It helps to plot the points on the graph and perform the Vertical Line Test (VLT):

The Vertical Line Test allows us to know whether or not a graph is actually a function. If a vertical line intersects the graph in all places at exactly one point, then the relation is a function.

As you can see in the attached screenshot, every vertical line drawn only has 1 point in it. This means that each x-value corresponds to exactly one y-value. The given relation passed the VLT. Therefore, the relation is a function.


Please mark my answers as the Brainliest if you find my explanation helpful :)

5 0
3 years ago
Oksana wrote the equation below on the whiteboard.
Kaylis [27]

Answer:

b = 7

Step-by-step explanation:

6 b + 6 = 48

Subtract 6 from each side

6b+6-6 = 48 -6

6b = 42

Divide each side by 6

6b/6 = 42/6

b = 7

8 0
3 years ago
Read 2 more answers
Other questions:
  • S=5(3.14)ab+5(3.14)s^2
    6·1 answer
  • Use rounding or compatible numbers to estimate each product or quotient.
    15·1 answer
  • Can you please help me with this equation:<br> 3x-4y = 8 <br> 18x-5y=10
    12·1 answer
  • What is the following sum? 5(3sqrtx)+9(3sqrtx)
    13·2 answers
  • Find the equation of this line
    15·2 answers
  • BRAINLIEST TO THE PERSON THAT ANSWERS FIRST
    8·1 answer
  • Please help ill give u brainliest!!!
    15·2 answers
  • A total of 553 tickets were sold for the school play. They were either adult tickets or student tickets. There were 53 more stud
    5·2 answers
  • Jordan has 28 golf balls. 28 golf balls in 4 rows and 7 columns. Of the 28 golf balls, 17 are yellow. How many golf balls are ye
    11·1 answer
  • What is the equation of x2 + 6x + 8 + 0 algebraically
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!