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3 years ago

So... if bedbugs live in beds, where do cockroaches live?

Physics

2 answers:

Deffense [45]3 years ago

6 0

Answer:

oo.p i wish I could answer that

Explanation:

mel-nik [20]3 years ago

6 0

Answer:

Sewers and possibly your basement

Explanation:

Anywhere warm, dark and wet

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An airplane cruises at 850 km/h relative to the air. It is flying from Denver, Colorado, due west to Reno, Nevada, a distance of

skad [1K]

Answer:

difference in flight time= 0.3023 hour

Explanation:

The question is incomplete, but I found it in your textbook.

Spped of aircraft = 850 km/h

Opposing speed of wind = 90km/h

Hence, the net speed when it's travelling west = 850 - 90 = 760 km/hr

The distance covered = 1200km

time taken = distance/ time = 1200/ 760 = 1.5789 hours

When coming back, the speed of the wind is complementary to the speed of the aircraft so

net speed when it's coming back = 850 +90 = 940 km/hr

time taken in this instance = 1200/ 940 = 1.2765 hours

Hence, the difference in flight time= 1.5789 - 1.2765 = 0.3023 hour

8 0

3 years ago

The speed of light in a vacuum is approximately 0.3 gm/s. What is the speed of light in meters per second?

klemol [59]

We have to convert Gm/s to m/s.

As $1 \ Gm/s = 10^9 \ m/s$

Therefore the speed of light in vacuum,

$c = 0.3 \ Gm/s = 0.3 \times 10^9 \ m/s \\\\ c= 3 \times 10^8 \ m/s$

Thus, the speed of light in m/s is $3 \times 10^8 \ m/s$

7 0

3 years ago

What are the steps to the scientific method

just olya [345]

Answer:

question, report, observe, research, draw conclusions, hypothesize, test hypothesis, experiment

Explanation:

3 0

4 years ago

A jet aircraft is traveling at 260 m/s in horizontal flight. The engine takes in air at a rate of 53.3 kg/s and burns fuel at a

IrinaVladis [17]

Answer:

The thrust of the jet engine is 4188.81 N.

Explanation:

Given that,

Speed = 260 m/s

Rate in air= 53.3 kg/s

Rate of fuel = 3.63 kg/s

Relative speed = 317 m/s

We need to calculate the rate of mass change in the rocket

Using formula of rate of mass

$\dfrac{dM}{dt}=\dfrac{dM_{a}}{dt}+\dfrac{dM_{f}}{dt}$

Put the value into the formula

$\dfrac{dM}{dt}=53.3+3.63$

$\dfrac{dM}{dt}=56.93\ kg/s$

We need to calculate the thrust of the jet engine

Using formula of thrust

$T=\dfrac{dM}{dt}u-\dfrac{dM_{a}}{dt}v$

Put the value into the formula

$T=56.93\times317-53.3\times260$

$T=4188.81\ N$

Hence, The thrust of the jet engine is 4188.81 N.

7 0

4 years ago

A plane is flying due west at 34 m/s. It encounters a wind blowing at 19 m/s south. Find the resultant veloci

Drupady [299]

Answer:

<em>The resultant velocity has a magnitude of 38.95 m/s</em>

Explanation:

<u>Vector Addition</u>

Given two vectors defined as:

$\vec v_1=(x_1,y_1)$

$\vec v_2=(x_2,y_2)$

The sum of the vectors is:

$\vec v=(x_1+x_2,y_1+y_2)$

The magnitude of a vector can be calculated by

$d=\sqrt{x^2+y^2}$

Where x and y are the rectangular components of the vector.

We have a plane flying due west at 34 m/s. Its velocity vector is:

$\vec v_1=(-34,0)$

The wind blows at 19 m/s south, thus:

$\vec v_2=(0,-19)$

The sum of both velocities gives the resultant velocity:

$\vec v =(-34,-19)$

The magnitude of this velocity is:

$d=\sqrt{(-34)^2+(-19)^2}$

$d=\sqrt{1156+361}=\sqrt{1517}$

d = 38.95 m/s

The resultant velocity has a magnitude of 38.95 m/s

3 0

3 years ago