In both magnitude and direction since acceleration is a vector quantity
        
                    
             
        
        
        
The reciprocal of the total resistance is equal to the sum of the reciprocals of the component resistances:
1/(120.7 Ω) = 1/<em>R₁</em> + 1/(221.0 Ω)
1/<em>R₁</em> = 1/(120.7 Ω) - 1/(221.0 Ω)
<em>R₁</em> = 1 / (1/(120.7 Ω) - 1/(221.0 Ω)) ≈ 265.9 Ω
 
        
             
        
        
        
Using V= vo +at with Vo = 0 and a= 4m/sec2. 
V= 0+ 4x8= 32m/s
        
                    
             
        
        
        
Answer:
<h2>
128.61 Watts</h2>
Explanation:
Average power done by the torque is expressed as the ratio of the workdone by the toque to time.
Power = Workdone by torque/time
Workdone by the torque = 
 = 
I is the rotational inertia = 16kgm²



To get the angular acceleration, we will use the formula;


Workdone by the torque = 16 * 1.28 * 12.56
Workdone by the torque = 257.23 Joules
Average power done by the torque = Workdone by torque/time
=  257.23/2.0
= 128.61 Watts
 
        
             
        
        
        
Answer:
the answer is d
Explanation:
you get exhausted at the middle because it is steep.