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3 years ago

Which artist of the northern European Renaissance, shown in this self-portrait, was also a block printer and engraver?

Physics

2 answers:

kicyunya [14]3 years ago

6 0

It's very hard to see the self-portrait, so I can't identify him.

zloy xaker [14]3 years ago

4 0

I just took the test with my son, the answere is Albrecht Durer. I hope this helps, you can check it on google :)

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A massive truck of 1200N moving with a velocity of 2m/s hits a stationary mass of 30N. if the both bodies move together after th

kicyunya [14]

Answer:

<em>The common speed is 1.95 m/s </em>

Explanation:

<u>Law Of Conservation Of Linear Momentum </u>

It states that the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is

P=mv.

If we have a system of bodies, then the total momentum is the sum of all of them:

$P=m_1v_1+m_2v_2+...+m_nv_n$

If a collision occurs, the velocities change to v' and the final momentum is:

$P'=m_1v'_1+m_2v'_2+...+m_nv'_n$

In a system of two masses, the law of conservation of linear momentum

is written as:

$m_1v_1+m_2v_2=m_1v'_1+m_2v'_2$

If both masses stick together after the collision at a common speed v', then:

$m_1v_1+m_2v_2=(m_1+m_2)v'$

The common velocity after this situation is:

$\displaystyle v'=\frac{m_1v_1+m_2v_2}{m_1+m_2}$

The truck of m1=1200 N (weight) travels at v1=2 m/s and hits a stationary mass (v2=0) of m2=30 N (weight). After the bodies collide, they keep moving together. Before we can calculate the common speed, we need to calculate the masses of the bodies, since they are given as weights.

$m_1=\frac{P_1}{g}=\frac{1200}{9.8}=122.45 Kg$

$m_2=\frac{P_2}{g}=\frac{30}{9.8}=3.06 Kg$

Now calculate the common speed:

$\displaystyle v'=\frac{122.45 * 2+3.06 * 0}{122.45+3.06}$

$\displaystyle v'=\frac{244.9}{125.51}=1.95\ m/s$

The common speed is 1.95 m/s

7 0

3 years ago

A horse is working steadily, providing 750 W of output power. How much food energy does the horse need to work for 1 hour, to th

Valentin [98]

Answer:

Under assumption that all food energy that needs the horse is transformed into work, then the horse needs approximately 3 megajoules of food energy to work for 1 hour.

Explanation:

Since horse is working steadily, the power experimented by the horse ( $\dot W$ ), measured in watts, is at constant rate. Then, the work needed by the horse ( $W$ ), measured in joules, is equal to that power multiplied by time ( $\Delta t$ ), measured in seconds. That is:

$W = \dot W\cdot \Delta t$ (1)

If we know that $\dot W = 750\,W$ and $\Delta t = 3600\,s$ , then the work needed for the horse is:

$W = (750\,W)\cdot (3600\,s)$

$W = 2.7\times 10^{6}\,J$

$W = 2.7\,MJ$

Under assumption that all food energy that needs the horse is transformed into work, then the horse needs approximately 3 megajoules of food energy to work for 1 hour.

7 0

2 years ago

Society is not affected by an individual's choice to use tobacco products. True or False

Mnenie [13.5K]

I took the test and it was FALSE.

Believe me

6 0

2 years ago

Read 2 more answers

The mass of a basketball is three times greater than the mass of a softball. Compare the momentums of a softball and a basketbal

ki77a [65]

Answer:

The momentum of the basketball is three times that of the softball. Momentum equals mass times velocity. Therefore, if the basketball and softball are moving at the same velocity, and the basketball has three times the mass of the softball, the basketball has three times the momentum of the softball.

Explanation:

pa brainliest

5 0

2 years ago

I really need the answer

Vilka [71]

Answer:

The first answer is correct. All of the other options include sound, which travels by material force, and can not be transmitted in a vacuum. Infra-red, radio, and microwaves are all different frequencies of light, and can thus travel through a vacuum.

7 0

3 years ago