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Agata [3.3K]
3 years ago
10

g A 5.60-kilogram hoop starts from rest at a height 1.80 m above the base of an inclined plane and rolls down under the influenc

e of gravity. What is the linear speed of the hoop's center of mass just as the hoop leaves the incline and rolls onto a horizontal surface? (Neglect friction.)
Physics
2 answers:
noname [10]3 years ago
6 0

Answer:

Linear speed = 4.2 m/s

Explanation:

Potential Energy at top = Kinetic Energy at bottom

Now, KE is the sum of linear and rotational kinetic energy.

Thus,

mgh = (1/2)mv² + (1/2)Iω²

Moment of Inertia for hoop; I = mr² Also, angular velocity; ω = v/r

Thus,

mgh = (1/2)mv² + (1/2)(mr²)(v/r)² = mgh = (1/2)mv² + (1/2)mv²

mgh = mv²

The m will cancel out and so;

gh = v²

9.81(1.80) = v²

v² = 17.658

v = √17.658

v = 4.2 m/s

swat323 years ago
4 0

Answer:

4.24m/s

Explanation:

Potential energy at the top= kinetic energy at the button

But kinetic energy= sum of linear and rotational kinetic energy of the hoop

PE= mgh

KE= 1/2 mv^2

RE= 1/2 I ω^2

Where

m= mass of the hoop

v= linear velocity

g= acceleration due to gravity

h= height

I= moment of inertia

ω= angular velocity of the hoop.

But

I = m r^2 for hoop and ω = v/r

giving

m g h = 1/2 m v^2 + 1/2 (m r^2) (v^2/r^2) = 1/2 m v^2 + 1/2 m v^2 = m v^2

and m's cancel

g h = v^2

Hence

v= √gh

v= √10×1.8

v= 4.24m/s

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Answer:

Average mass of acar in the US (in kg) = 1440 kg

Explanation:

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3 years ago
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2 years ago
State three differences between solid friction and viscosity​
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2 years ago
A mass hanging from a spring is set in motion and its ensuing velocity is given by v (t )equals 2 pi cosine pi t for tgreater th
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Answer:

2(maximum), -2(minimum), -2(maximum).

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zhannawk [14.2K]

The final velocity of the train after 8.3 s on the incline will be 12.022 m/s.

Answer:

Explanation:

So in this problem, the initial speed of the train is at 25.8 m/s before it comes to incline with constant slope. So the acceleration or the rate of change in velocity while moving on the incline is given as 1.66 m/s². So the final velocity need to be found after a time period of 8.3 s. According to the first equation of motion, v = u +at.

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