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3 years ago

In a two planet system, does an increase in planet velocity result in a decreased period?

2 answers:

5 0

From the formula,
v=2πr/T
V(velocity is inversely related to T),so when v increases then time period will decrease.
Option a is correct.

Pani-rosa [81]3 years ago

5 0

THE ANSWER IS D...No, if velocity becomes too great, the planet can escape the Sun's gravitational pull.

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A uniform bridge 20.0 m long and weighing 400000 N is supported by two pillars located 3.00 m from each end. If a 19600 N car is

Svetradugi [14.3K]

Answer:

P = 238475 N

Q = 181125

Explanation:

From the diagram attached below,

For the bridge to be at equilibrium,

Sum of upward force = sum of downward force

P+Q = 400000+19600

P+Q = 419600.................. Equation 1

Taking moment about support A

sum of clockwise moment = sum of anti clockwise moment.

400000(10-3)+19600(8-3) = Q(20-6)

2800000+98000 = 16Q

2898000 = 16Q

Q = 2898000/16

Q = 181125 N.

Substitute the value of Q into equation 1

P+181125 = 419600

P = 419600-181125

P = 238475 N.

Hence, support A exert a force of 238475 N and support B exert a force of 181125 N

7 0

3 years ago

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Suppose 2.10 C of positive charge is distributed evenly throughout a sphere of 1.30-cm radius. 1) What is the charge per unit vo

Anuta_ua [19.1K]

Answer:

$\rho=2.28\times 10^5\ C/m^3$

Explanation:

Given that,

Charge, Q = 2.1 C

The radius of sphere, r = 1.3 cm = 0.013 m

We need to find the charge per unit volume for this situation. It can be calculated a follows:

$\rho=\dfrac{Q}{\dfrac{4}{3}\pi r^3}\\\\\rho=\dfrac{2.1}{\dfrac{4}{3}\pi \times (0.013)^3}\\\\\rho=2.28\times 10^5\ C/m^3$

So, the charge per unit volume is $2.28\times 10^5\ C/m^3$ .

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Alex777 [14]

Answer:

Explanation:

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VLD [36.1K]

Answer: 100 units

Explanation:

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3 years ago