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Ymorist [56]
3 years ago
14

Donna stretched a spring to increase its length. Nearby in an electrical device, a positive charge attracted a negative charge.

Which statement is true about the spring and the negative charge?
A. They both experienced contact forces.
B. They both experienced non-contact forces.
C. The spring experienced a contact force and the charge experienced a non-contact force.
D. The spring experienced a non-contact force and the charge experienced a contact force.
Physics
1 answer:
timurjin [86]3 years ago
7 0

C. The spring experienced a contact force and the charge experienced a non-contact force

Explanation:

In physics, there are two types of forces:

  • Contact forces: contact forces are those where a contact between the objects involved is needed, in order to have the force. Examples of contact forces are the force of friction (the contact between the two surfaces is needed), or the elastic force in a spring (in fact, the spring needs to be physically in contact with something that stretches it)
  • Non-contact forces: non-contact forces are those where no contact is needed between the objects, so they can be exerted at a distance. Examples are the gravitational force (two masses exert a force on each other even from a distance) or the electric force (two charges exert a force on each other even from a distance).

Therefore, in this example:

  • The spring experiences a contact force
  • The two charges experience a non-contact force

So the correct answer is

C. The spring experienced a contact force and the charge experienced a non-contact force

Learn more about forces:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

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3 years ago
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Which of the following is always true about a synthesis reaction?
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3 years ago
A student pushes a 0.2 kg box against a spring causing the spring to compress 0.15 m. When the spring is released, it will launc
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Answer:

The maximum height the box will reach is 1.72 m

Explanation:

F = k·x

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Therefore the force, F of the spring = 300 N/m×0.15 m = 45 N

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Work, W, done by the spring = \frac{1}{2} kx^2 and the kinetic energy gained by the box is given by KE = \frac{1}{2} mv^2

Since work done by the spring = kinetic energy gained by the box we have

\frac{1}{2} mv^2 =  \frac{1}{2} kx^2  therefore we have v = \sqrt{\frac{kx^2}{m} } = x\sqrt{\frac{k}{m} } = 0.15\sqrt{\frac{300}{0.2} } = 5.81 m/s

Therefore the maximum height is given by

v² = 2·g·h or h = \frac{v^2}{2g} = \frac{5.81^{2} }{2*9.81} = 1.72 m

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Answer:

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