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Ymorist [56]
3 years ago
14

Donna stretched a spring to increase its length. Nearby in an electrical device, a positive charge attracted a negative charge.

Which statement is true about the spring and the negative charge?
A. They both experienced contact forces.
B. They both experienced non-contact forces.
C. The spring experienced a contact force and the charge experienced a non-contact force.
D. The spring experienced a non-contact force and the charge experienced a contact force.
Physics
1 answer:
timurjin [86]3 years ago
7 0

C. The spring experienced a contact force and the charge experienced a non-contact force

Explanation:

In physics, there are two types of forces:

  • Contact forces: contact forces are those where a contact between the objects involved is needed, in order to have the force. Examples of contact forces are the force of friction (the contact between the two surfaces is needed), or the elastic force in a spring (in fact, the spring needs to be physically in contact with something that stretches it)
  • Non-contact forces: non-contact forces are those where no contact is needed between the objects, so they can be exerted at a distance. Examples are the gravitational force (two masses exert a force on each other even from a distance) or the electric force (two charges exert a force on each other even from a distance).

Therefore, in this example:

  • The spring experiences a contact force
  • The two charges experience a non-contact force

So the correct answer is

C. The spring experienced a contact force and the charge experienced a non-contact force

Learn more about forces:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

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slava [35]

Answer:

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5 0
2 years ago
How long was a 60 W light bulb turned on if it used a total of 580 J of energy?
icang [17]
Here's the tool you need.  You can't answer the question without this:

           "1 watt"
means
           "1 joule of energy, generated, used, or moved, every second".

So      60 watts  =  60 joules per second

           Total energy generated,
            used, or moved                  = (power) x (time).

                                     580 joules  =  (60 watts) x (time)

Divide each side
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7 0
3 years ago
A crate lies on a plane tilted at an angle θ = 22.5 ∘ to the horizontal, with μk = 0.19.
ValentinkaMS [17]

A) 2.03 m/s^2

Let's start by writing the equation of the forces along the directions parallel and perpendicular to the incline:

Parallel:

mg sin \theta - \mu_k R = ma (1)

where

m is the mass

g = 9.8 m/s^2 the acceleration of gravity

\theta=22.5^{\circ}

\mu_k = 0.19 is the coefficient of friction

R is the normal reaction

a is the acceleration

Perpendicular:

R-mg cos \theta =0 (2)

From (2) we find

R=mg cos \theta

And substituting into (1)

mg sin \theta - \mu_k mg cos \theta = ma

Solving for a,

a=g sin \theta - \mu_k g cos \theta = (9.8)(sin 22.5)-(0.19)(9.8)(cos 22.5)=2.03 m/s^2

B) 5.94 m/s

We can solve this part by using the suvat equation

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

Here we have

v = ?

u = 0 (it starts from rest)

a=2.03 m/s^2

s = 8.70 m

Solving for v,

v=\sqrt{u^2+2as}=\sqrt{0+2(2.03)(8.70)}=5.94 m/s

6 0
3 years ago
a 2000 kg truck is moving eastward at 25 m/s. it collides inelastically with a 1500 kg truck traveling southward at 30 m/s. they
Otrada [13]

According to the given statement Final velocity when they stick together is 8.735i^ + 11.25j^​

<h3>What is collision and momentum?</h3>

The unit of momentum is kg ms -1. Momentum is a vector parameter that is influenced by the object's direction. During collisions involving objects, momentum is a relevant concept. The final velocity before a collision between two objects equals the total motion after the impact (in the absence of external forces).

<h3>Briefing:</h3>

From conservation of momentum

Initial momentum = final momentum

m u +M U =(m+M) V

2000×25 i^ +1500×30 j^​ =(2000+1500) V

V = 8.735i^ + 11.25j^​

Final velocity when they stick together is 8.735i^ + 11.25j^​

To know more about Collide visit:

brainly.com/question/27993473

#SPJ4

The complete question is -

A 2000 kg truck is moving eastward at 25 m/s. it collides inelastically with a 1500 kg truck traveling southward at 30 m/s. they collide at the intersection. Find the direction and magnitude of velocity of the wreckage after the collision, assuming the vehicles stick together after the collision.

6 0
1 year ago
When driving straight down the highway at a constant velocity you have to give the engine a little gas (which means an added ext
Alona [7]

Answer:

Explanation:

This does not violate Newton's 1st law because the net force would still be 0 in order to produce uniform motion (aka constant velocity). The other forces acting on the vehicles is air resistance which is non-zero. So we need car internal force to counter balance this force, which require extra gas for the car.

7 0
3 years ago
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