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Amanda [17]
3 years ago
14

How is the probability that an electron will be detected related to the absolute value of ψ?

Physics
1 answer:
Dafna1 [17]3 years ago
3 0

Answer:

D) The probability is proportional to the absolute value of ψ squared.

Explanation:

since ψ² represents probability density (ψ alone represents probability amplitude) , then the probability is proportional to ψ².

also since the probability to over all the possible values inside the volume element should sum 1

∫ψ²  dV = 1

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Suppose you are playing hockey on a new-age ice surface for which there is no friction between the ice and the hockey puck. You
BlackZzzverrR [31]

Answer:

<em>Not slow down or speed up</em>.

Explanation:

Hitting the puck accelerates the speed of the puck from zero to the speed with which it leaves at the instance they lose contact. Since there is no friction between the puck and the ice, there will be no force decelerating or accelerating the hockey puck, allowing the puck to move away and remain in motion without speeding up or slowing down indefinitely theoretically.

4 0
4 years ago
The force that keeps two surfaces at rest from sliding over each other is
natka813 [3]
Friction is the correct answer.
8 0
3 years ago
Albert uses as his unit of length (for walking to visit his neighbors or plowing his fields) the albert (a), the distance albert
True [87]

To solve this problem, we know that:

1 Albert = 88 meters

1 A = 88 m

The first thing we have to do is to square both sides of the equation:

(1 A)^2 = (88 m)^2

1 A^2 = 7,744 m^2

<span>Since it is given that 1 acre = 4,050 m^2, so to reach that value, 1st let us divide both sides by 7,744:</span>

1 A^2 / 7,744 = 7,744 m^2 / 7,744

(1 / 7,744) A^2 = 1 m^2

Then we multiply both sides by 4,050.

(4050 / 7744) A^2 = 4050 m^2

0.523 A^2 = 4050 m^2

<span>Therefore 1 acre is equivalent to about 0.52 square alberts.</span>

7 0
3 years ago
Which refers to the amount of heat required to change the temperature of 1 gram of a substance by 1°C and is related to the chem
timama [110]

Answer:

Specific heat

Explanation:

8 0
3 years ago
the half-life of carbon-14 is 5,730 years. After 11,460 year, how much of original carbon-14 remains?
Inessa [10]

Via the half-life equation:

A_{final}=A_{initial}(\frac{1}{2})^{\frac{t}{h}}

Where the time elapse is 11,460 year and the half-life is 5,730 years.

A_{final}=A_{initial}(\frac{1}{2})^\frac{11460}{5730} \\\\A_{final}=A_{initial}\frac{1}{4} \\\\A_{final}=\frac{1}{4}A_{initial}

Therefore after 11,460 years the amount of carbon-14 is one fourth (1/4) of the original amount.

6 0
3 years ago
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