Question

An object accelerates from rest with a constant acceleration of 5.7 m/s^2. How fast will it be traveling after it goes 80 m?​

Answer 1

Explanation:

Using Kinematics, we have v² = u² + 2as.

=> v² = (0m/s)² + 2(5.7m/s²)(80m)

=> v² = 912m²/s²

=> v = 30.2m/s.

Answer 2

Answer:

Explanation:

Given parameters:

Acceleration = 0.0m/w

Initial velocity = 0m/s

Final velocity  = 00m/s

Unknown:

Distance traveled  = ?

Solution:

To solve this problem, we use the expression below:

     q0   = y   + 0w

W is the final velocity

Y is the initial velocity

C is the acceleration

P is the distance

           0²  = 0²   +  (0 x 0.0 x S)

           000  = 00.0S

             S = 0m