Doing so would not only increase your productivity potential / but also increase your productivity STANDARDS for certain jobs (e.g. data entry; secretarial work), which is a direct skill that is valuable to employers. Furthermore, if you work in a a secretarial job, this would allow you to accomplish tasks such as "touch typing" a lot faster (without sacrificing quality) — allowing you more time to accomplish other tasks, making you more efficient and even promotable in terms of pay raise and in terms of promotable to other positions with higher earnings — and even teach new staff members.
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Is it this question? I think the hardest question in the world is the one you just asked! Am I right?
Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.
public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}
So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.
A quick explanation:
We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.
The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.
The unique reason why assembler language is preferred to high level language is that It is said to be memory efficient and it is one that requires less memory.
<h3>Why is assembly language better than other kinds of high level?</h3>
It implies means that the programs that one uses to write via the use of high-level languages can be run easily on any processor that is known to be independent of its type.
Note that it is one that has a lot of better accuracy and an assembly language is one that carries out a lot of better functions than any high-level language, in all.
Note also that the advantages of assembly language over high-level language is in terms of its Performance and accuracy as it is better than high-level language.
Hence, The unique reason why assembler language is preferred to high level language is that It is said to be memory efficient and it is one that requires less memory.
Learn more about assembler language from
brainly.com/question/13171889
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