<span>We know that the momentum keeps constant in a inelastic collisions, so the product of mass and speed do not change:
m1 * v1 + m2 * v2 = m * v
1 * 1 + 5 * 0 = (1 + 5) * v
1 = 6 * v
v = 1/6 m/s
So the final speed of the 6 kg chunk will travel at 0.167 m/s</span>
Answer:
a) FE = 0.764FG
b) a = 2.30 m/s^2
Explanation:
a) To compare the gravitational and electric force over the particle you calculate the following ratio:
(1)
FE: electric force
FG: gravitational force
q: charge of the particle = 1.6*10^-19 C
g: gravitational acceleration = 9.8 m/s^2
E: electric field = 103N/C
m: mass of the particle = 2.2*10^-15 g = 2.2*10^-18 kg
You replace the values of all parameters in the equation (1):
![\frac{F_E}{F_G}=\frac{(1.6*10^{-19}C)(103N/C)}{(2.2*10^{-18}kg)(9.8m/s^2)}\\\\\frac{F_E}{F_G}=0.764](https://tex.z-dn.net/?f=%5Cfrac%7BF_E%7D%7BF_G%7D%3D%5Cfrac%7B%281.6%2A10%5E%7B-19%7DC%29%28103N%2FC%29%7D%7B%282.2%2A10%5E%7B-18%7Dkg%29%289.8m%2Fs%5E2%29%7D%5C%5C%5C%5C%5Cfrac%7BF_E%7D%7BF_G%7D%3D0.764)
Then, the gravitational force is 0.764 times the electric force on the particle
b)
The acceleration of the particle is obtained by using the second Newton law:
![F_E-F_G=ma\\\\a=\frac{qE-mg}{m}](https://tex.z-dn.net/?f=F_E-F_G%3Dma%5C%5C%5C%5Ca%3D%5Cfrac%7BqE-mg%7D%7Bm%7D)
you replace the values of all variables:
![a=\frac{(1.6*10^{-19}C)(103N/C)-(2.2*10^{-18}kg)(9.8m/s^2)}{2.2*10^{-18}kg}\\\\a=-2.30\frac{m}{s^2}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B%281.6%2A10%5E%7B-19%7DC%29%28103N%2FC%29-%282.2%2A10%5E%7B-18%7Dkg%29%289.8m%2Fs%5E2%29%7D%7B2.2%2A10%5E%7B-18%7Dkg%7D%5C%5C%5C%5Ca%3D-2.30%5Cfrac%7Bm%7D%7Bs%5E2%7D)
hence, the acceleration of the particle is 2.30m/s^2, the minus sign means that the particle moves downward.
It’s either 0.05 or 20. Assuming that the coefficient friction is a damping factor, I feel like 0.05 would be correct m
The best question that could prompt a scientific investigation is: <u>What substances dissolve in ocean water?</u>
This way the person experimenting can use several variables and make observations. Upon making observations, the person can be able to gather as much data as he can in order to answer the original question that he asked.