First, lets assume x = 5, to start us off. (2 * 5 + 9) = (5 + 1) (I assume that in between the two equations is an = sign because without it, the entire problem would make no sense.) (10 + 9) = (6) 19 = 6 Not the same. So, I think that it would be lower than 5. Let us continue
Answer: Every polygon that is not a triabgle (3 vertices), quadrilateral (4 vertices) or pentagon (5 vertices) has more than 5 vertices. So it would be a hexagon, heptagon, etc.