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Law Incorporation [45]
3 years ago
9

How many liters of hydrogen gas is formed from the complete reaction of 15.9 g c? assume that the hydrogen gas is collected at a

pressure of 1.0 atm and a temperature of 360 k ?
Chemistry
2 answers:
ololo11 [35]3 years ago
7 0
C + H2O -> H2 + CO
n(C) = 15.9/12 = 1.325 (mol)
=> n(H2) = 1.325 mol
We have:
PV = nRT
=> V = (nRT)/P
(R = 22.4/273 = 0.082)
V = (1.325 x 0.082 x 360)/1 = 39.114 (L)
Nostrana [21]3 years ago
3 0

Answer : The volume of hydrogen gas formed is, 39.2 liters.

Explanation :

The balanced chemical reaction is:

C(s)+H_2O(g)\rightarrow CO(g)+H_2(g)

First we have to calculate the moles of carbon (C).

\text{Moles of }C=\frac{\text{Mass of }C}{\text{Molar mass of }C}

Molar mass of carbon = 12 g/mole

Mass of carbon = 15.9 g

\text{Moles of }C=\frac{15.9g}{12g/mole}=1.325mole

Now we have to calculate the moles of H_2 gas.

From the reaction we conclude that,

As, 1 mole of carbon reaction to give 1 mole of hydrogen gas

So, 1.325 mole of carbon reaction to give 1.325 mole of hydrogen gas

Now we have to calculate the volume of hydrogen gas by using ideal gas equation.

PV=nRT

where,

P = Pressure of H_2 gas = 1.0 atm

V = Volume of H_2 gas = ?

n = number of moles  H_2 = 1.325 mole

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of H_2 gas = 360 K

Putting values in above equation, we get:

1.0atm\times V=1.325mole\times (0.0821L.atm/mol.K)\times 360K

V=39.2L

Therefore, the volume of hydrogen gas formed is, 39.2 liters.

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Zinc metal reacts with hydrochloric acid to produce zinc(II) chloride and hydrogen gas. How many liters of hydrogen gas will be
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Answer:

0.120 L of hydrogen gas will be produced

Explanation:

Step 1: Data given

Mass of zinc = 10.0 grams

Volume of hydrochloric acid = 23.8 mL

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Molar mass of zinc =65.38 g/mol

Step 2: The balanced equation

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Step 3: Calculate moles Zinc

Moles Zn = mass Zn / molar mass Zn

Moles Zn = 10.0 grams / 65.38 g/mol

Moles Zn  =  0.153 moles

Step 4: Calculate moles HCl

Moles HCl = molarity * volume

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Step 5: Calculate limiting reactant

For 1 mol Zn, we need 2 moles HCl to produce 1 mol ZnCl2 and 1 mol H2

HCl is the limiting reactant. It will completely be consumed (0.01071 moles)

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There will remain 0.153 - 0.005355 = 0.147645 moles

Step 6: Calculate moles H2

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Step 7: Calculate volume H2

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0.005355 moles = 22.4 * 0.005355 = 0.120 L = 120 mL

0.120 L of hydrogen gas will be produced

4 0
3 years ago
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