the accepted value for density of sugar is 2.165/g/cm^3. A student measured a sugar cube as 5cm by 5cm by 5 cm and the mass is 2
1 answer:
You might be interested in
Answer:
a) HNO3
b) 26.8g (3 s.f.)
c) 1.29g (3 s.f.)
Please see the attached pictures for full solution.
To balance an equation, ensure that the number of atoms for each element is the same on both sides.
Answer : The value of equilibrium constant for this reaction at 328.0 K is
Explanation :
As we know that,
where,
= standard Gibbs free energy = ?
= standard enthalpy = 151.2 kJ = 151200 J
= standard entropy = 169.4 J/K
T = temperature of reaction = 328.0 K
Now put all the given values in the above formula, we get:
The relation between the equilibrium constant and standard Gibbs free energy is:
where,
= standard Gibbs free energy = 95636.8 J
R = gas constant = 8.314 J/K.mol
T = temperature = 328.0 K
K = equilibrium constant = ?
Now put all the given values in the above formula, we get:
Therefore, the value of equilibrium constant for this reaction at 328.0 K is
Answer: 26.54 grams
Explanation:
To calculate the moles :
is the limiting reagent as it limits the formation of product and
is the excess reagent
According to stoichiometry :
As 1 moles of give = 3 moles of
Thus 0.369 moles of give =
of
Mass of
Thus 26.54 g of will be produced from the given mass.