C = 2πr
17 = 2(3.14)(r)
17 = 2(3.14r)
17 = 6.28r
6.28 6.28
2.71 ≈ r
Answer:
A = 0.8 litres
B = 0.7 litres
C = 0.5 litres
D = 0.2 litres
Step-by-step explanation
Here's what we know:
1. Jug A = B + .1 litres
2. Jug C = B - 200 (or 0.2 litres)
3. Jug D = .25 x A
4. Jug A + Jug B = 1.5 litres
In problem 1, we learned that Jug A has .1 litres more than Jug B and in problem 4, the two of them added together are 1.5 litres. To solve this we can combine the problems.
B + .1 litres + B = 1.5 litres
2B + .1 = 1.5
Subtract .01 from each side and you have 2B = 1.4
Divide each side by 2 and you have B = 0.7 litres
Plug this info into problem 1 and you can solve for A. (0.7 + 0.1 = 0.8)
Plug this info into problem 2 and you can solve for C. (0.7 - 0.2 = 0.5)
Since you have A, you can use that info to solve problem 3 (0.25 x 0.8 = 0.2)
Answer: x ≥ 11
Step-by-step explanation: We wrote an inequality to represent this situation.
0.001 x 425 = .425
answer C. $0.425
Answer:
(14-8)
Step-by-step explanation:
Heres why:
Pedmas
P= Parenthesis
E=Exponents
D=Division
M=Multiplication
A=Addition
S= Subtraction
Do that in order.
