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Leokris [45]
3 years ago
6

Rutherford’s experiment showed that some substances allowed alpha particles to pass through them Frequently.he theorized this ha

ppened because the nuclei were .
Chemistry
1 answer:
Svetllana [295]3 years ago
6 0
Made of smaller subatomic particles.
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How does experiments help scientist learn about the world
PSYCHO15rus [73]

Experiments test the scientists' ideas.

5 0
3 years ago
When 250 ml of water is added to 35 ml of 0.2 M HCl
Paladinen [302]
Assuming that you’re looking for the concentration of water in the solution, then it would be 0.028 M.

You would have to use the formula:
c1v1 = c2v2, where c =concentration and
v = volume

C1 = ?
V1 = 250 mL
C2 = 0.2 M
V2 = 35 mL

C1 x 250 mL = 0.2 M x 35 mL

C1 = (0.2 M x 35 mL) / 250 mL

C1 = 0.028 M of water added to 35mL of 0.2M HCl

Therefore, there is 0.028 M of water added to 35mL of 0.2M HCl
8 0
3 years ago
Read 2 more answers
Calculating Density Warm Up
Artist 52 [7]

Answer:

2

Explanation:

33-25=8

48/8=6

6 0
3 years ago
Compared to an atom of C-12, an atom of C-14 has
KonstantinChe [14]

Explanation:

Carbon-12 atoms have stable nuclei because of the 1:1 ratio of protons and neutrons.

Carbon-14 atoms have nuclei which are unstable. C-14 atoms will undergo alpha decay and produce atoms of N-14. Carbon-14 dating can be used to determine the age of artifacts which are not more than 50,000 years old.

8 0
3 years ago
A balloon contains 2.0 L of air at 101.5 kPa . You squeeze the balloon to a volume of 0.25 L.
8_murik_8 [283]
<h3>Answer:</h3>

812 kPa

<h3>Explanation:</h3>
  • According to Boyle's law pressure and volume of a fixed mass are inversely proportional at constant absolute temperature.
  • Mathematically, P\alpha \frac{1}{V}

At varying pressure and volume;

P1V1=P2V2

In this case;

Initial volume, V1 = 2.0 L

Initial pressure, P1 = 101.5 kPa

Final volume, V1 = 0.25 L

We are required to determine the new pressure;

P2=\frac{P1V1}{V2}

Replacing the known variables with the values;

P2=\frac{(101.5)(2.0L)}{0.25L}

           = 812 kPa

Thus, the pressure of air inside the balloon after squeezing is 812 kPa

8 0
3 years ago
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