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Blizzard [7]
3 years ago
12

Omg imgonnafailnfiedkla

Chemistry
1 answer:
Flura [38]3 years ago
4 0

Answer:

Glucose and oxygen are required for cellular respiration. As the law of conversation states, in a biochemical reaction, mass is conserved. The mass of hydrogen in the glucose is therefore conserved in the water molecules products.

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What are the products?
LuckyWell [14K]
I think it would be option 4?
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3 years ago
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What is the number of moles of solute in a .3 molality solution containing .10 kg of solvent?
denpristay [2]
Concentration can be expressed in different forms: molarity, molality, normality, percentage, part per million and many more. For molality, it is a unit of concentration expressed as moles of solute per kilogram of solvent. Therefore,

0.3 = moles solute/0.10 kg solvent
moles solute = 0.03 moles
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4 years ago
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What is the sign of the heat change for an exothermic reaction? for an endothermic reaction?
Julli [10]

A system that releases heat to the surroundings, an exothermic reaction, has a negative ΔH by convention, because the enthalpy of the products is lower than the enthalpy of the reactants of the system. The enthalpies of these reactions are less than zero, and are therefore exothermic reactions

3 0
3 years ago
The chemical equation for the reaction of baking soda (sodium bicarbonate, nahco3) and vinegar (acetic acid, ch3cooh) may be wri
satela [25.4K]
<h3><u>Answer;</u></h3>

Step 1;  NaHCO3(s) + CH3COOH(l)

Step 2 ; CO2(g)

<h3><u>Explanation;</u></h3>
  • The chemical equation for the reaction of baking soda (sodium bicarbonate, NaHCO3) and vinegar (acetic acid, CH3COOH) reaction occurs in two steps.

Step 1;  

  • A double displacement reaction in which acetic acid in the vinegar reacts with sodium bicarbonate to form sodium acetate and carbonic acid:
  • Equation;

NaHCO3(s)+ CH3COOH(l) → CH3COONa(aq) + H2CO3(l)

Step 2;

  • Carbonic acid is unstable and undergoes a decomposition reaction to produce the carbon dioxide gas:

H2CO3(l) → H2O(l) + CO2(g)

3 0
3 years ago
The elementary reaction 2H2O(g)↽−−⇀2H2(g)+O2(g) 2H2O(g)↽−−⇀2H2(g)+O2(g) proceeds at a certain temperature until the partial pres
Dima020 [189]

Answer:

6.25\times 10^{-6} is the value of the equilibrium constant at this temperature.

Explanation:

Equilibrium constant in terms of partial pressure is defined as the ratio of partial pressures of products to the partial pressures  of reactants each raised to the power equal to their stoichiometric ratios. It is expressed as K_{p}

2H_2O(g)\rightleftharpoons 2H_2(g)+O_2(g)

Partial pressures at equilibrium:

p^o_{H_2O}=0.070 atm

p^o_{H_2}=0.0035 atm

p^o_{O_2}=0.0025 atm

The equilibrium constant in terms of pressures is given as:

K_p=\frac{(p^o_{H_2})^2\times (p^o_{O_2})}{(p^o_{H_2O})62}

K_p=\frac{(0.0035 atm)^2\times 0.0025 atm}{(0.070 atm)^2}=6.25\times 10^{-6}

6.25\times 10^{-6} is the value of the equilibrium constant at this temperature.

5 0
3 years ago
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