Question

100 points for correct answer

Answer 1

Answer:

$\dfrac{x}{3}+\dfrac{3}{y}$

Step-by-step explanation:

Given fraction:

$\dfrac{xy+9}{3y}$

$\textsf{Apply the fraction rule} \quad \dfrac{a+b}{c}=\dfrac{a}{c}+\dfrac{b}{c}:$

$\implies \dfrac{xy}{3y}+\dfrac{9}{3y}$

Rewrite 9 as 3 · 3:

$\implies \dfrac{xy}{3y}+\dfrac{3 \cdot 3}{3y}$

Cancel the common factor y in the first fraction and the common factor 3 in the second fraction:

$\implies \dfrac{x\diagup\!\!\!\!y}{3\diagup\!\!\!\!y}+\dfrac{\diagup\!\!\!\!3 \cdot 3}{\diagup\!\!\!\!3y}$

$\implies \dfrac{x}{3}+\dfrac{3}{y}$