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Black_prince [1.1K]
4 years ago
15

9|9-8x|=2x+3 solve the equation

Mathematics
1 answer:
laila [671]4 years ago
8 0

Answer:

the answer is this because x=39/37,6/5

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Triangle ABD is a right-angled triangle, with ∠ABD = 90◦ . The point C lies on side BD. CD has length 20 cm. ∠CDA = 35.8 ◦ and ∠
pishuonlain [190]
The length is 46.10 cm.

Since ∠BCA = 50.5°, ∠ACD = 180-50.5 =129.5°.  This means that ∠CAD = 180-(129.5+35.8) = 14.7°.  We can now use the law of sines;

sin 14.7/20 = sin 35.8/x

Cross multiply:
x*sin 14.7 = 20*sin 35.8

Divide both sides by sin 14.7:
x = (20*sin 35.8)/(sin 14.7) = 46.10
6 0
3 years ago
circle 1 is centered at 4,3 and has a radius of 5 centimeters circle 2 is centered at 6,-2 and has a radius of 15 centimeters. W
wolverine [178]
We know that
<span>Figures can be proven similar if one, or more, similarity transformations (reflections, translations, rotations, dilations) can be found that map one figure onto another.
In this problem to prove circle 1 and circle 2 are similar, a translation and a scale factor (from a dilation) will be found to map one circle onto another.

</span>we have that
 <span>Circle 1 is centered at (4,3) and has a radius of 5 centimeters
</span><span> Circle 2 is centered at (6,-2) and has a radius of 15 centimeters
</span>
step 1
<span>Move the center of the circle 1 onto the center of the circle 2
</span>the transformation has the following rule
(x,y)--------> (x+2,y-5)
so
(4,3)------> (4+2,3-5)-----> (6,-2)
so
center circle 1 is now equal to center circle 2 
<span>The circles are now concentric (they have the same center)
</span>
step 2
A dilation is needed to increase the size of circle 1<span> to coincide with circle 2
</span>
scale factor=radius circle 2/radius circle 1-----> 15/5----> 3

radius circle 1 will be=5*scale factor-----> 5*3-----> 15 cm
radius circle 1 is now equal to radius circle 2 

A translation, followed by a dilation<span> will map one circle onto the other, thus proving that the circles are similar</span>


5 0
4 years ago
Elena's math class had 25 students yesterday. she miscounted the class total and recorded it as 20 students. What is Elena's per
adelina 88 [10]
Elena had a 5% error
8 0
3 years ago
Find the distance from point C to point D.
sineoko [7]

The tangent or tanθ in a right-angle triangle is the ratio of its perpendicular to its base. The distance from point C to point D is 258.8 meters.

<h3>What is Tangent (Tanθ)?</h3>

The tangent or tanθ in a right-angle triangle is the ratio of its perpendicular to its base. it is given as,

\rm Tangent(\theta) = \dfrac{Perpendicular}{Base}

where,

θ is the angle,

Perpendicular is the side of the triangle opposite to the angle θ,

The base is the adjacent smaller side of the angle θ.

The distance from point C to D is equal to the distance from point A to B. Therefore, the height of the building can be written as,

Tan(25°) = AB / BC

Tan(25°) × 555 m = AB

AB = 258.8 meters

Hence, the distance from point C to point D is 258.8 meters.

Learn more about Tangent (Tanθ):

brainly.com/question/10623976

#SPJ1

3 0
3 years ago
1. The 4th, 5th, and 6th terms of an arithmetic sequence are 19, 23, and 27 respectively. What is the first
babymother [125]

Answer: 7

Step-by-step explanation: The only pattern in this sequence that I can see is addition by 4. Therefore, the 3rd term is 15, the 2nd is 11, the 1st is 7.

Please consider Brainliest.

8 0
2 years ago
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