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Firdavs [7]
3 years ago
10

How many molecules are present in a sample of carbon dioxide, CO2 with a mass of 168.2?

Chemistry
1 answer:
Hoochie [10]3 years ago
6 0

Answer:

Explanation:

Always remember that 1 mole is just a way of saying 6.02 x 10^23 molecules. Because this is a huge number it is easier to use moles. It corresponds nicely ecause 12 grams of carbon is one mole (note the Mr of carbon is 12) and 44g of CO2 is one mole of CO2 (note that CO2 has Mr 44).  You need to use the equation n = m/Mr . In words this is: number of moles = the mass (in grams) divided by the Molar Mass.  You can think of this as the number of moles is equal to the mass of the amount you have divided by the mass of one mole (the molar mass).   To find the molar mass of CO2 you need to use the periodic table.   12 + 16 + 16 = 44  So you need to do:  168.2 divided by 44 which will give you number of moles.

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What is the temperature of 1.485 moles of N₂ gas at a pressure of 1.072 atm and a volume of 20 L?
morpeh [17]

Answer:

178.67K

Explanation:

PV=nRT

T=PV/nR

= 1.072atm*20L/1.485mol*0.0821LatmK^-1

=178.67K

8 0
3 years ago
What is the mass of silver (107.87 g/mol) produced by the reaction of 3.00 moles of copper with 3.00 moles of silver nitrate?Cu
vladimir2022 [97]

Answer: 323.61 g of Ag will be produced

Explanation:

The given balanced chemical reaction is :

Cu+2AgNO_3\rightarrow Cu(NO_3)_2+2Ag

According to stoichiometry :

2 moles of AgNO_3 require 1 mole of Cu

Thus 3.00 moles of  AgNO_3 will require=\frac{1}{2}\times 3.00=1.50moles  of Cu

Thus AgNO_3 is the limiting reagent as it limits the formation of product.

As 2 moles of AgNO_3 give =  2 moles of Ag

Thus 3.00 moles of AgNO_3 give =\frac{2}{2}\times 3.00=3.00moles  of Ag

Mass of Ag=moles\times {\text {Molar mass}}=3.00moles\times 107.87g/mol=323.61g

Thus 323.61 g of Ag will be produced from the given moles of both reactants.

3 0
3 years ago
The model below shows an atom of an element. 9 light grey and 8 dark grey balls sit at the center with 2 concentric black rings
aleksley [76]

Answer:

sorry if this is a bit late but i know what your talking about and your answer would be 8

stay happy!!

3 0
3 years ago
Read 2 more answers
What volume would 2.25 moles of Ne gas occupy at STP?
Dafna1 [17]
As we know that one mole of any Ideal gas at standard temperature and pressure occupies exactly 22.4 dm³ volume.

Solution for problem:

When 1 mole Neon (Ne) occupies 22.4 dm³ at STP then the volume occupied by 2.25 moles of Neon is calculated as,

                                             = ( 22.4 dm³ × 2.25 moles ) ÷ 1 mole
                
                                             = 50.4 dm³                   1dm³ = 1 L

Result:

So
, 50.4 dm³ (Liter) volume will be occupied by 2.25 moles of Neon gas if it acts ideally at STP.
8 0
3 years ago
A student states that this structural formula represents a hydrocarbon.
goblinko [34]
.
the answer is Yes, a hydrocarbon is any compound that contains hydrogen and oxygen.

5 0
3 years ago
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