The correct answer is letter D. distance to a star.
In astrophysics, M = m - 5 log(d/10)
where
m - apparent magnitude
<span>M - absolute magnitude </span>
<span>m - apparent magnitude </span>
<span>d - distance measured in parsec </span>
C₅H₁₂ + 8O₂ = 5CO₂ + 6H₂O
5CO₂ - 10O
6H₂O - 6O
16O - 8O₂
8 moles of molecular oxygen are consumed
<u>Answer;</u>
-energy
According to the Kinetic Molecular Theory, the absolute temperature of a gas is directly related to average molecular kinetic<u> energy</u>.
<u>Explanation;</u>
- Kinetic molecular theory is a theory that explains that the particles of a gas are in constant random motion, exhibiting perfectly elastic collisions.
- This theory may be explained using Boyle's and Charles's law. Such that the average kinetic energy of a given particles of a gas is directly proportion to the absolute temperature.
Answer:
Explanation:
The molar mass of a given substance corresponds and pertains to the unit mole of the mass substance which is stated in g/mol
no of moles of H = mass of H/molar mass of H
= 2 kg/ 2 g/mol
= 2000 g/ 2 g/mol
= 1000 moles
moles of O2 = mass (O2)/ molar mass (O2)
= 2 kg/ 32 g/mol
= 2000 g / 32 g/mol
= 62.5 moles
Total moles present = (1000 + 62.5) moles
= 1062.5 moles
= 1.063 kmol
Total mass = 2kg + 2kg
= 4 kg
no of moles = mass/molar mass
molar mass = mass/ no of moles
molar mass = 4 kg/ 1.063 kmol
molar mass = 3.763 kg/kmol
The specific volume of the final mixture can be determined by the relation:
![v_{mixture}=\dfrac{ V}{m}](https://tex.z-dn.net/?f=v_%7Bmixture%7D%3D%5Cdfrac%7B%20V%7D%7Bm%7D)
where;
V = 3 m³
m = 4 kg
![v_{mixture}=\dfrac{ 3 \ m^3}{4 \ kg}](https://tex.z-dn.net/?f=v_%7Bmixture%7D%3D%5Cdfrac%7B%203%20%5C%20m%5E3%7D%7B4%20%5C%20kg%7D)
= 0.75 m³/ kg
For the final volume, The molar specific volume is:
![v_M = M_{mixture} *v_{mixture}](https://tex.z-dn.net/?f=v_M%20%3D%20M_%7Bmixture%7D%20%2Av_%7Bmixture%7D)
where;
![M_{mixture} = 3.763](https://tex.z-dn.net/?f=M_%7Bmixture%7D%20%3D%203.763)
![v_{mixture} = 0.75 \ m^3/ kg](https://tex.z-dn.net/?f=v_%7Bmixture%7D%20%3D%20%200.75%20%5C%20%20m%5E3%2F%20kg)
∴
![v_M = 3.763 \ kg/mol \times 0.75 \ m^3/kg](https://tex.z-dn.net/?f=v_M%20%3D%203.763%20%5C%20kg%2Fmol%20%5Ctimes%200.75%20%5C%20m%5E3%2Fkg)
![\mathbf{v_M = 2.82 \ m^3/kmol}](https://tex.z-dn.net/?f=%5Cmathbf%7Bv_M%20%3D%202.82%20%5C%20m%5E3%2Fkmol%7D)
<span>the electron configuration ... Write the ground-state electron configuration of alead atom. 1. [Xe] 4f 145d...</span>