Question

An aqueous 0.300 M glucose solution is prepared with a total volume of 0.150 L. The molecular weight of

Answer 1

Answer:

8.11g

Explanation:

Given parameters:

Molarity of aqueous solution = 0.3M

total volume  = 0.15L

Molecular weight of glucose  = 180.6g/mol

Unknown:

Mass of glucose needed in the solution = ?

Solution:

To solve this problem, we need to understand molarity.

Molarity is the number of moles of solute in a given volume of solution. In this problem, the solute here is the glucose and the solvent is water.

      Molarity  = $\frac{number of moles of solute}{volume of solution}$

A solution is made up of solute and solvent.

   now, let us solve for the number of moles of the solute which is glucose;

   Number of moles of glucose  = molarity x volume of solution;

                                                      = 0.3 x 0.15

                                                      = 0.045mole

Now to find the mass of glucose;

        mass of glucose  = number of moles x molar mass

             input the parameters;

       

         Mass of glucose  = 0.045  x 180.16 = 8.11g