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irakobra [83]
2 years ago
7

Emma pays $24 to rent a boat at the lake for up to 6 hours. She constructs the inequality and number line below to represent the

number of hours,x, she can use the boat.

Mathematics
1 answer:
Sergeu [11.5K]2 years ago
6 0

Answer:

where are the options??

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What is the value of 3/5+2/7
netineya [11]

Answer:

0.8 is your answer

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Helpp please thanksss
Brilliant_brown [7]

Answer:

The function show the value of the machinery after "t" years.

So After "4" years... Input "t" as 4 to get its value

f(t) = 12,500 - 1,600(4)

=$6,100

OPTION C IS LEGIT!!!

8 0
3 years ago
Dwayne drove 18 miles to the airport to pick up his father and then returned home. On the return trip he was able to drive an av
Nesterboy [21]

Answer:

30 mph

Step-by-step explanation:

Let d = distance (in miles)

Let t = time (in hours)

Let v = average speed driving <u>to</u> the airport (in mph)

⇒ v + 15 = average speed driving <u>from</u> the airport (in mph)

Using:  distance = speed x time

\implies t=\dfrac{d}{v}

Create two equations for the journey to and from the airport, given that the distance one way is 18 miles:

\implies t=\dfrac{18}{v}  \ \ \textsf{and} \ \  t=\dfrac{18}{v+15}

We are told that the total driving time is 1 hour, so the sum of these expressions equals 1 hour:

\implies \dfrac{18}{v} +\dfrac{18}{v+15}=1

Now all we have to do is solve the equation for v:

\implies \dfrac{18(v+15)}{v(v+15)} +\dfrac{18v}{v(v+15)}=1

\implies \dfrac{18(v+15)+18v}{v(v+15)}=1

\implies 18(v+15)+18v=v(v+15)

\implies 18v+270+18v=v^2+15v

\implies v^2-21v-270=0

\implies (v-30)(v+9)=0

\implies v=30, v=-9

As v is positive, v = 30 only

So the average speed driving to the airport was 30 mph

(and the average speed driving from the airport was 45 mph)

8 0
2 years ago
Read 2 more answers
3 2/3 times 5 1/7 = ?/3 times ?/7 =
Ymorist [56]

Answer:

is that 32 / 3 or 3^2/3 ...?

Step-by-step explanation:

if 32/3 and 51/7

then answer will be 1120/17

4 0
2 years ago
Write the slope intercept form of the equation of the line through the given points x intercept of -5 and y intercept of -1. Pls
soldier1979 [14.2K]

bearing in mind that an x-intercept is when the graph touches the x-axis and when that happens y = 0, and a y-intercept is  when the graph touches the y-axis and when that happens x = 0.

\bf \underset{x-intercept}{(\stackrel{x_1}{-5}~,~\stackrel{y_1}{0})}\qquad \underset{y-intercept}{(\stackrel{x_2}{0}~,~\stackrel{y_2}{-1})} ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-1}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-5)}}}\implies \cfrac{-1}{0+5}\implies -\cfrac{1}{5}

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{1}{5}}[x-\stackrel{x_1}{(-5)}] \\\\\\ y=-\cfrac{1}{5}(x+5)\implies y = -\cfrac{1}{5}x-1

4 0
3 years ago
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