Answer:
he aight but he best gurl
Explanation:
Answer:
8.68 L is the new volume
Explanation:
You use Boyle's law for this.

= first pressure
= second pressure
= first volume
= second volume
Convert pressure from atm to mmHg (use same units):
5.97 x 760 = 4537.2 -> 4.54 x 10³
...maintain 3 significant figures in calculation, and round as needed...
(4.54 x 10³ mmHg)(2.79 L) = (1460 mmHg)(
)
(4.54 x 10³ mmHg)(2.79 L) / (1460 mmHg) =
= 8.68 L
Hope this helps :)
Answer:
There are four major classes of biological macromolecules (carbohydrates, lipids, proteins, and nucleic acids)
Explanation:
There are four major classes of biological macromolecules (carbohydrates, lipids, proteins, and nucleic acids), and each is an important component of the cell and performs a wide array of functions. ... Biological macromolecules are organic, meaning that they contain carbon.
Answer:
34.3 g
Explanation:
Step 1: Write the balanced equation
2 CH₃CH₂OH ⇒ CH₃CH₂OCH₂CH₃ + H₂O
Step 2: Calculate the moles corresponding to 50.0 g of CH₃CH₂OH
The molar mass of CH₃CH₂OH is 46.07 g/mol.
50.0 g × 1 mol/46.07 g = 1.09 mol
Step 3: Calculate the theoretical moles of CH₃CH₂OCH₂CH₃ produced
The molar ratio of CH₃CH₂OH to CH₃CH₂OCH₂CH₃ is 2:1. The moles of CH₃CH₂OCH₂CH₃ theoretically produced are 1/2 × 1.09 mol = 0.545 mol.
Step 4: Calculate the real moles of CH₃CH₂OCH₂CH₃ produced
The percent yield of the reaction is 85%.
0.545 mol × 85% = 0.463 mol
Step 5: Calculate the mass corresponding to 0.463 moles of CH₃CH₂OCH₂CH₃
The molar mass of CH₃CH₂OCH₂CH₃ is 74.12 g/mol.
0.463 mol × 74.12 g/mol = 34.3 g
Answer:3
Explanation: if I was like a rated wave