All categories

2 years ago

In which item is energy is stored in the form of gravitail energy

1 answer:

8 0

Gravitational energy is stored potential energy in an object based on its high position compared to a lower position. A pendulum converts potential energy from gravity into kinetic energy and back again.

Hope that helps

You might be interested in

Why is east Texas shaded green and west Texas shaded brown

kodGreya [7K]

I believe that east Texas is shaded green because it either has a grassy plain or there are a lot of grassy hills and I think that west Texas is shaded brown because it is like a desert.

8 0

3 years ago

Read 2 more answers

How many neutrons are in an isotope of nitrogen-16?

Elza [17]

Mass number = number of protons + number of neutrons
number of protons = atomic number =7
number of neutrons= mass number - number of protons=16-7=9
Answer is B.9.

8 0

2 years ago

What us true when an ion is formed?

aleksandr82 [10.1K]

B) there is an unequal number of electrons and protons

5 0

3 years ago

Which set of these comparisons is incorrect? (more stable means it has a more negative energy.)

Lady bird [3.3K]

I think your anwser ahould be b!

4 0

3 years ago

The reaction: 2 CO(l) + O2(g) ⇄2 CO2(g) with a H = −25.0 kJ/mol, is at equilibrium. Which of the following lists three ways thi

elena-s [515]

Answer:

Option B and D both have 3 ways to shift the reaction to the right

Explanation:

The reaction 2 CO(l) + O2(g) ⇄2 CO2(g) is exothermic because ΔH = -25 kJ < 0 This means heat will be released

Therefore, increasing the temperature will shift the equilibrium to the left, while decreasing the temperature will shift the equilibrium to the right.

A. remove CO2, lower pressure and remove CO

⇒ Lowering the pressure will shift the equilibrium to the side with most moles of gas : On the left side there are 3 moles, on the right side 2 moles. By lowering the pressure, the equilibrium will shift to the left.

B remove CO2, raise pressure and add CO

⇒ By raising the pressure, the equilibrium will shift to the side with the lesser amount of moles of gas. This is the right side.

⇒ Remove CO2: the equilibrium will shift to the side of CO2 ,so the reaction will shift toward products to replace the product removed. (The right side).

⇒ Add CO: the equilibrium will shift to the side of CO2, so the reaction will shift toward the products side to reduce the added CO. (The right side).

C raise temperature, lower pressure and remove O2

⇒ Increasing the temperature will shift the equilibrium to the left

D add O2, raise pressure and lower temperature

⇒ decreasing the temperature will shift the equilibrium to the right

⇒ By raising the pressure, the equilibrium will shift to the side with the lesser amount of moles of gas. This is the right side.

⇒ Add O2: the equilibrium will shift to the side of CO2, so the reaction will shift toward the products side to reduce the added O2. (The right side).

E remove CO2, increase volume and lower temperature

⇒ decreasing the temperature will shift the equilibrium to the right

⇒ Remove CO2: the equilibrium will shift to the side of CO2 ,so the reaction will shift toward products to replace the product removed. (The right side).

⇒ Increase volume : with a pressure decrease due to an increase in volume, the side with more moles is more favorable. The equilibrium will shift to the left side.

8 0

3 years ago