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slega [8]
3 years ago
13

An inflatable raft that you have jumped in to escape the monsters has 4500 cubic inches of air inside it when fully inflated. It

loses air at a rate of decrease 6.5% each day. How much air will be left in the raft after 8 days?
Mathematics
1 answer:
DedPeter [7]3 years ago
8 0

Answer:

2628.48 cubic inches

Step-by-step explanation:

The inflatable raft has 4500 cubic inches of air inside it when fully inflated.

The inflatable raft loses air at a rate of a decrease 6.5% each day.

Now, we have to calculate the volume of air that will be left in the raft after 8 days.

Therefore, the volume of air left in the raft after 8 days will be 4500[1-\frac{6.5}{100} ]^{8} =2628.48 cubic inches. (Answer)

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24-3x=2x-1
+3x. +3x

24=5x-1
+1. +1

25=5x

X=5
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2 years ago
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"in a small town, 60% of the households have dogs. if 5 households are randomly selected, what is the probability that at least
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4/5 houses have a dog

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Fill in the table using this function rule y=-4x+1
andreev551 [17]

Answer:

There isnt any table

Step-by-step explanation:

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2 years ago
Find the missing endpoint if S is the midpoint RT
Stolb23 [73]

Answer:

  10. T(-20, 9)

  11. R(-1, -9)

  12. D(-6, 5)

Step-by-step explanation:

The relationship between end points and the midpoint can be solved generically for one of the end points. That relation can be used for the different points in these problems.

__

<h3>generic solution</h3>

The coordinates of midpoint M is related to the coordinates of end points A and B by ...

  M = (A +B)/2

This can be solved for end point B, given end point A and midpoint M:

  2M = A +B

  2M -A = B

Then the generic equation for end point B given end point A and midpoint M is ...

  B = 2M -A

__

In each of the numbered problems, the midpoint and one end point are given. These can be matched with the variables in the above formula, so the solution is simply a matter of arithmetic. Beware all the minus signs.

<h3>10.</h3>

  T = 2R -S

  T = 2(-9, 4) -(2, -1) = (2(-9) -2, 2(4) +1)

  T = (-20, 9)

__

<h3>11.</h3>

  R = 2S -T

  R = 2(-4, -6) -(-7, -3) = (2(-4) +7, 2(-6) +3)

  R = (-1, -9)

__

<h3>12.</h3>

  B = (A +C)/2 = ((-9, -4) +(-1, 6))/2 = (-9 -1, -4 +6)/2 = (-10, 2)/2

  B = (-5, 1) . . . . the missing midpoint of AC

  D = 2B -E . . . . the missing end point of BD

  D = 2(-5, 1) -(-4, -3) = (2(-5) +4, 2(1) +3)) = (-10 +4, 2 +3)

  D = (-6, 5)

8 0
2 years ago
ennifer has been saving for college for 57 months. The first month, she saved $11. She was able to save more money each month th
crimeas [40]
The is an arthitmetic sequence, so let's determined all the aspects and factors using the details and information from this word problem.
The first term (a) = 11, number of terms (n) = 57, the sum of nth term (Sn) = 19,779.
Let the common difference between the amount of money she saved more each month is d.
Sn = n/2(2a+(n-1)d)
19,799 = 57/2(2(11) + (57-1)d)
19,799 = 28.5(22 + 56d)
19,799 = 627 + 1,596d
    -627  -627
____________________
   19,172 = 1,596d
___________________
             1,596

d= 12.01253.

In conclusion, she saved about $12 more each month.
3 0
3 years ago
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