Answer:
On 5th day and 13th day Attendance was equal for both plays and it was
231 for each .
Step-by-step explanation:
In order to find same attendance ,we need plug both equation equal
-x^2+26x+126 = 8x+191
-x^2+26x-8x+126-191 = 0
-x^2 +18x-65 =0
multiplying both sides by -1 ,we get
x^2 -18x+ 65 =0
(x-5) (x-13) =0
x =5 and x =13
On 5th day and 13th day attendance was same.
And attendance can be obtained by plugging x =5 in either of equation
y = 8(5)+191
= 40 +191
= 231
Answer: The only factor of 13 and 80 is 1.
Step-by-step explanation:
Factors of 13: 1, 13.
Factors of 80: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80.
The only factor they have the same is 1.
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2×5^{2} if you don't understand its 2 times 5 to the second power.
Equal sets have the exact same elements, so they must have the same number of elements. Therefore, equal sets must also be equivalent. No, not all equivalent sets are also equal sets