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3 years ago

(-18)-(4) please help thank you

Mathematics

2 answers:

Temka [501]3 years ago

5 0

Answer:

-22

Step-by-step explanation:

-18 - 4 = 22

Alexxx [7]3 years ago

3 0

Answer:

-22

Step-by-step explanation:

18 + 4 = 22

then just add the negative to 22

-22

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Help! I have no idea!

qwelly [4]

I believe is C and D because

C. The original rectangle width is 2m and the length is 4m. And to make the other rectangle they are adding .5 m to both the width and length

D. The original rectangle has a width of 2m and length of 4m. To make the other rectangle they are substracting 1 m from the width and length

5 0

3 years ago

25 points!! please answer

melomori [17]

ac is the answer

hope that helps

6 0

3 years ago

Read 2 more answers

The measures of the angles of a triangle are (3x – 100)°, (x – 10)°, and (x – 10)°.

statuscvo [17]

Answer:

x = 60

largest angle = 80°

Step-by-step explanation:

the sum of all three angles in a triangle = 180°

(3x - 100) + (x - 10) + (x - 10) = 180

simplify:

5x = 300

x = 60

angles are 80°, 50°, and 50°

7 0

3 years ago

State one form of the Law of Cosines and provide a trick for writing the other two forms and explain when Law of Cosines should

Yuki888 [10]

Solving for Angles

$\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos∠C \\ \frac{a^2 - b^2 + c^2}{2ac} = cos∠B \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos∠A$

* Do not forget to use the inverse function towards the end, or elce you will throw your answer off!

Solving for Edges

$\displaystyle b^2 + a^2 - 2ba\:cos∠C = c^2 \\ c^2 + a^2 - 2ca\:cos∠B = b^2 \\ c^2 + b^2 - 2cb\:cos∠A = a^2$

You would use this law under two conditions:

One angle and two edges defined, while trying to solve for the third edge
ALL three edges defined

* Just make sure to use the inverse function towards the end, or elce you will throw your answer off!

_____________________________________________

Now, JUST IN CASE, you would use the Law of Sines under three conditions:

Two angles and one edge defined, while trying to solve for the second edge
One angle and two edges defined, while trying to solve for the second angle
ALL three angles defined [of which does not occur very often, but it all refers back to the first bullet]

* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.

I am delighted to assist you at any time.

7 0

2 years ago

Which expression is equivalent to 6^2 times 6^6? a. 6^8 b. (6^3)^5 c. 6^12 d. 6^8/6

ratelena [41]

Step-by-step explanation:

Rule:

When exponents multiply, they're adding.

Multiply:

${6}^{2} \times {6}^{6} = {6}^{2 + 6} = {6}^{8}$

Option A is correct.

8 0

2 years ago