Find the length and width of a rectangle with an area of 2x^2+x-3
2 answers:
The length and width of a rectangle with an area of
is:
l = 2x + 3; w = x - 1
Hope I helped! :)
Can you mark my answer the brainliest, maybeee....
2x^2 + x -3 can be factorised
<span>[2x + 3][x - 1] </span>
<span>As length times width = area </span>
<span>one possible set of measurements are </span>
<span>length = [2x + 3] </span>
<span>width = [x-1] </span>
You might be interested in
Answer:
118
Step-by-step explanation:
10-4xy
10-4(9)(-3)
10-36(-3)
10+108
118
M=0-5/1-0
m=-5/1=-5
y-y1=m*(x-x1)
y-5=-5(x-0)
y-5=-5x
y=-5x+5
Answer:
the answer is c starting with -5720
subtract 6 from the 21x+6. Then divide by 21. The answer is going to be -6/21