Answer:
the concentration of the solution is 0.00906 M
Explanation:
Given the data in the question;
we know that from Nernst Equation;
E = E⁰ - ((0.0592/n) logQ)
now, E₀ for concentration cell is 0
n for this redox is 2
concentration of the unknown solution is x
so we substitute
0.045 = 0 - ( 0.0592 / 2)log( x/0.300 ))
0.045 = -0.0296log( x/0.300 )
divide both side by 0.0296
1.52 = -log( x/0.300 )
x/0.300 = 
x/0.300 = 0.0301995
we cross multiply
x = 0.300 × 0.0301995
x = 0.00906 M
Therefore, the concentration of the solution is 0.00906 M
The liquid particles would have moved randomly because of the increase in thermal energy. They would move randomly and would be floating in the bottle moving randomly. The liquid would turn into gas form. Meaning that you would have water particles floating in the bottle moving randomly.
The correct awnser is yes, hope this helps
Answer:
P₂ = 2.19 atm
Explanation:
Given data:
Initial volume = 1.5 L
Initial pressure =1 atm
Initial temperature = 273K
Final temperature = 26°C (26+273 = 299 K)
Final volume = 0.75 L
Final pressure = ?
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₂ = P₁V₁ T₂/ T₁ V₂
P₂ = 1 atm × 1.5 L × 299 K / 273 K × 0.75 L
P₂ = 448.5 atm .L. K / 204.75 K.L
P₂ = 2.19 atm
