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Phoenix [80]
3 years ago
8

What is the theoretical yield of sodium oxide (Na₂O) in grams when 20.0g of calcium oxide (CaO) reacts with an excess amount of

Sodium chloride? *
10 points
Captionless Image
10.0g
22.1g
32.9g
5.6g
Chemistry
2 answers:
ad-work [718]3 years ago
6 0

Answer:

22.1g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CaO + 2NaCl —> Na2O + CaCl2

Next, we shall determine the mass of CaO that reacted and the mass of Na2O produced from the balanced equation.

This is illustrated below:

Molar mass of CaO = 40 + 16 = 56g/mol

Mass of CaO from the balanced equation = 1 x 56 = 56g

Molar mass of Na2O = (23x2) + 16 = 62g/mol

Mass of Na2O from the balanced equation = 1 x 62 = 62g

From the balanced equation above,

56g of CaO reacted to produce 62g of Na2O.

Finally, we can determine the theoretical yield of Na2O as follow:

From the balanced equation above,

56g of CaO reacted to produce 62g of Na2O.

Therefore, 20g of CaO will react to produce = (20 x 62)/56 = 22.1g of Na2O.

Therefore, the theoretical yield of Na2O is 22.1g

Taya2010 [7]3 years ago
3 0

Answer:

22.1 g

Explanation:

The balanced reaction equation which serves as a guide in solving the problem is given as;

CaO(s) + 2NaCl(aq) ------> Na2O(s) + CaCl2(aq)

The question clearly specifies that sodium chloride is the reactant in excess. This means that calcium oxide should be used to calculate the theoretical yield of sodium oxide.

Number of moles of calcium oxide reacted = mass of calcium oxide / molar mass of calcium oxide

Molar mass of calcium oxide = 56.0774 g/mol

Mass of calcium oxide = 20.0g

Number of moles of calcium oxide = 20.0 g/ 56.0774 g/mol = 0.3566 moles

From the balanced reaction equation;

1 mole of calcium oxide produces 1 mole of sodium oxide

Therefore, 0.3566 moles of calcium oxide will produce 0.3566 moles of sodium oxide.

Mass of sodium oxide produced = number of moles × molar mass

Molar mass of sodium oxide= 61.9789 g/mol

Mass of sodium oxide = 0.3566 moles × 61.9789 g/mol

Mass of sodium oxide= 22.1 g

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strojnjashka [21]
Answer: SO₂ + H₂O → HSO₃ ⁻ + H⁺

Justification:

1) Ionization means formation of ions.

2) Ions are species that are not neutral, they are charged, in virtue of having less or more electrons than protons.

3) Ionization may happen in different environments.

4) Ionic compunds, like Mg(OH)₂ dissociate into ions (ionize) in water. That is the example shown in the fourth option:

Mg(OH)₂ → Mg ²⁺ + 2OH⁻

5) How much a ionic compound dissociates in water (ionize) depends on the Ksp (product solubility constant) which measures the concentrations of the ions that can be in the solution.


6) The Ksp for Mg(OH)₂ is very low, meaning that it will slightly ionize.

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8 0
3 years ago
Is selenium tetrafluoride an ionic or covalent bond?
nasty-shy [4]

Answer:

Synthesis

The first reported synthesis of selenium tetrafluoride was by Paul Lebeau in 1907, who treated selenium with fluorine:[1]

Se + 2 F2 → SeF4

A synthesis involving more easily handled reagents entails the fluorination of selenium dioxide with sulfur tetrafluoride:[2]

SF4 + SeO2 → SeF4 + SO2

An intermediate in this reaction is seleninyl fluoride (SeOF2).

Other methods of preparation include fluorinating elemental selenium with chlorine trifluoride:

3 Se + 4 ClF3 → 3 SeF4 + 2 Cl2

Structure and bonding

Selenium in SeF4 has an oxidation state of +4. Its shape in the gaseous phase is similar to that of SF4, having a see-saw shape. VSEPR theory predicts a pseudo-trigonal pyramidal disposition of the five electron pairs around the selenium atom. The axial Se-F bonds are 177 pm with an F-Se-F bond angle of 169.2°. The two other fluorine atoms are attached by shorter bonds (168 pm), with an F-Se-F bond angle of 100.6°. In solution at low concentrations this monomeric structure predominates, but at higher concentrations evidence suggests weak association between SeF4 molecules leading to a distorted octahedral coordination around the selenium atom. In the solid the selenium center also has a distorted octahedral environment.

Reactions

In HF, SeF4 behaves as a weak base, weaker than sulfur tetrafluoride, SF4 (Kb= 2 X 10−2):

SeF4 + HF → SeF3+ + HF2−; (Kb = 4 X 10−4)

Ionic adducts containing the SeF3+ cation are formed with SbF5, AsF5, NbF5, TaF5, and BF3.[3] With caesium fluoride, CsF, the SeF5− anion is formed, which has a square pyramidal structure similar to the isoelectronic chlorine pentafluoride, ClF5 and bromine pentafluoride, BrF5.[4] With 1,1,3,3,5,5-hexamethylpiperidinium fluoride or 1,2-dimethylpropyltrimethylammonium fluoride, the SeF62− anion is formed. This has a distorted octahedral shape which contrasts to the regular octahedral shape of the analogous SeCl62−. [5]

Explanation:

4 0
3 years ago
A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. Calculate the pressure when the volume is 1.41 L and the
Vlad1618 [11]

A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

<h3>What is Combined Gas Law ?</h3>

This law combined the three gas laws that is (i) Charle's Law (ii) Gay-Lussac's Law and (iii) Boyle's law.

It is expressed as

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

where,

P₁ = first pressure

P₂ = second pressure

V₁ = first volume

V₂ = second volume

T₁ = first temperature

T₂ = second temperature

Now put the values in above expression we get

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

\frac{1.02\ atm \times 2.30\ L}{281\ K} = \frac{P_2 \times 1.41\ L}{298\ K}

P_{2} = \frac{1.02\ atm \times 2.30\ L \times 298\ K}{281\ K \times 1.41\ L}

P₂ = 1.76 atm

Thus from the above conclusion we can say that A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

Learn more about the Combined gas Law here: brainly.com/question/13538773

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4 0
2 years ago
Lithium β is a solid phase of lithium still unknown to science. The only difference between it and ordinary lithium is that Lith
pychu [463]

Answer:

The density of Lithium β is 0.5798 g/cm³

Explanation:

For a face centered cubic (FCC) structure, there are total number of 4 atoms in the unit cell.

we need to calculate the mass of these atoms because density is mass per unit volume.

Atomic mass of Lithium is 6.94 g/mol

Then we calculate the mass of four atoms;

= 4 .atoms*\frac{1.mole}{6.022 X10^{23} .atoms} *\frac{6.94g}{mole} = 4.6097 X10^{-23} g

⇒next, we estimate the volume of the unit cell in cubic centimeter

given the edge length or lattice constant a = 0.43nm

a = 0.43nm = 0.43 X 10⁻⁹ m = 0.43 X 10⁻⁹ X 10² cm = 4.3 X 10⁻⁸cm

Volume of the unit cell = a³ = (4.3 X 10⁻⁸cm)³ = 7.9507 X 10⁻²³ cm³

⇒Finally, we calculate the density of Lithium β

Density = mass/volume

Density = (4.6097 X 10⁻²³ g)/(7.9507 X 10⁻²³ cm³)

Density = 0.5798 g/cm³

3 0
3 years ago
Which of the following has the smallest radius? <br> A. O^2- <br> B. F^- <br> C. Li^- <br> D. Be^2+
nordsb [41]

Answer : The correct option is, (D) Be^{2+}

Explanation :

Effective nuclear charge : It is defined as the attraction of the protons present in the nucleus of an atom to the outermost electrons.

For ions, the effective nuclear charge changes than the neutral atom.

There are two types of ions:

Cations: They are formed when an atom looses its valence electrons. They are positive ions.

Anions: They are formed when an atom gain electrons in its outermost shell. They are negative ions.

For positive ions, the removal of electron increases the nuclear charge for an outermost electron because the outermost electrons are more strongly attracted by the nucleus. Thus, the effective nuclear charge increases for cations.

From this we conclude that, the size of the cation is smaller than their neutral atom because it has less number of electrons while its nuclear charge remains the same. So, the nucleus attracts the electron more towards itself and leads to the decrease in size.

For negative ions, the addition of electron decreases the nuclear charge for an outermost electron because the outermost electrons are less strongly attracted by the nucleus. Thus, the effective nuclear charge decreases for anions.

From this we conclude that, the size of the anion is greater than their neutral atom because it has more number of electrons while its nuclear charge remains the same. So, the nucleus attracts the electron less towards itself and leads to the increase in size.

Thus, the increasing order of radius of ions will be:

Be^{2+}

Hence, the smallest radius of ion is, Be^{2+}

4 0
3 years ago
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