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Vladimir [108]
3 years ago
13

When methane is completely combusted in oxygen forming carbon dioxide and

Chemistry
1 answer:
Goshia [24]3 years ago
5 0

Answer:

The masses of the reactants and products are equal.

Explanation:

Hope this helps.

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A pharmacy intern is asked to prepare 3 L of a 30% w/v solution. T he pharmacy stocks the active ingredient in 8-ounce bottles o
MariettaO [177]

<u>Answer:</u> The number of bottles that will be needed are 6

<u>Explanation:</u>

We are given:

Amount of solution, the intern is asked to prepare = 3 L = 3000 mL   (Conversion factor:  1 L = 1000 mL)

Strength of solution needed = 30 % (w/v)

This means that in 100 mL of solution, the solute present is 30 grams

So, in 3000 mL of solution, the solute present will be = \frac{30}{100}\times 3000=900g

Active ingredient present in 1 bottle = 8 ounce of 70 % (w/v)

<u>Conversion factor used:</u> 1 ounce = 29.57 mL

So, 8ounce\times \frac{29.57mL}{1ounce}=236.6mL

Amount of active ingredient present in 1 bottle = 236.6\times \frac{70}{100}=165.6g

To calculate the number of bottles, we need to divide the total amount of solution needed by the amount of active ingredient present in 1 bottle, we get:

\text{Number of bottles}=\frac{\text{Amount of solution to prepare}}{\text{Amount of active ingredient in 1 bottle}}

Putting values in above equation, we get:

\text{Number of bottles}=\frac{900g}{165.6g}\\\\\text{Number of bottles}=5.43\approx 6

Hence, the number of bottles that will be needed are 6

6 0
3 years ago
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