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Over [174]
3 years ago
6

Does this graph represent a function? Why or why not?

Mathematics
1 answer:
Firlakuza [10]3 years ago
8 0
Where’s the graph????????????
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a coyote can run up to 43 mph while a rabbit can run up to 35 mph. Write two equivalent expressions and then find how many more
Dafna11 [192]
The coyote can run 48 more miles than the rabbit
8 0
3 years ago
What is the value of x?<br> X=32<br> X=36<br> X=37<br> X=40
kumpel [21]
A line is 180 degrees so write x+(4x-20)=180
5 0
4 years ago
Read 2 more answers
Determine which of the four levels of measurement​ (nominal, ordinal,​ interval, ratio) is most appropriate. ages of children: 3
gayaneshka [121]

Answer:

The level of variable ages of children is ratio.

Explanation:

Nominal scale is the one which takes categories as its values like gender of a person.

Ordinal scale is the one which is used to show the order of values with no clear difference among them like satisfaction level of people with a service.

Interval scale is the one which shows the clear order of values with clear difference between the values with out true zero.

Ordered scale is one which not only produces the order of variables but also makes the difference between variables known along with information on the value of true zero.

Therefore, the variable which is under consideration here is the ages of children, which takes the values 3,4,5,6 and 7 is a ratio scale.


6 0
3 years ago
If 3/4 of a stick of butter will make 3 dozen cookies how many sticks of butter will make be needed for 1 dozen
Lynna [10]

Answer:

\frac{1}{4} stick of butter

Step-by-step explanation:

\frac{3}{4} ÷ 3 = \frac{1}{4}

6 0
4 years ago
Convert the rectangular coordinates (-9, 3V3) into polar form. Express the angle
Whitepunk [10]

Answer:

(6\sqrt{3},\,\frac{5\pi}{6})

Step-by-step explanation:

The radius  r  can be found from the relationship

 r^2=x^2+y^2\\r^2=(-9)^2+(3\sqrt{3})^2\\r^2=81+27=108\\r=\sqrt{108}\\r=6\sqrt{3}

The point is in Quadrant II (-, +), so use the inverse cosine function to find the angle.

\cos{\theta}=\frac{x}{r}=\frac{-9}{6\sqrt{3}}\\\cos{\theta}=-\frac{9}{6\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}}\\\cos{\theta}=-\frac{9\sqrt{3}}{6\cdot3}\\\cos{\theta}=-\frac{\sqrt{3}}{2}\\\\\cos^{-1}\frac{-\sqrt{3}}{2}}=\frac{5\pi}{6}

See the attached image.

7 0
3 years ago
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