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4 years ago

Find the area of a trapezoid with bases 14 cm and 18 cm and height 10 cm.

Mathematics

1 answer:

4vir4ik [10]4 years ago

8 0

You should add the two bases and muliply them with the height and then divide with 2
(14+18)×10÷2=160

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What is answer for 10+(3+4-6+8) by using order of operation

Zina [86]

Answer:

The value of given expression is 19.

Step-by-step explanation:

The given expression is

$10+(3+4-6+8)$

According to the rule of BODMAS the order of operations is Bracket, Of, Division, Multiplication, Addition and Subtraction.

First we have to simplify the value of bracket.

$10+(3+4-6+8)=10+(15-6)$

$10+(3+4-6+8)=10+9$

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2 years ago

Write the equation of a parabola having the vertex (1, −2) and containing the point (3, 6) in vertex form. Then, rewrite the equ

In-s [12.5K]

PART A

The equation of the parabola in vertex form is given by the formula,

$y - k = a {(x - h)}^{2}$

where

$(h,k)=(1,-2)$

is the vertex of the parabola.

We substitute these values to obtain,

$y + 2 = a {(x - 1)}^{2}$

The point, (3,6) lies on the parabola.

It must therefore satisfy its equation.

$6 + 2 = a {(3 - 1)}^{2}$

$8= a {(2)}^{2}$

$8=4a$

$a = 2$
Hence the equation of the parabola in vertex form is

$y + 2 = 2 {(x - 1)}^{2}$

PART B

To obtain the equation of the parabola in standard form, we expand the vertex form of the equation.

$y + 2 = 2{(x - 1)}^{2}$

This implies that

$y + 2 = 2(x - 1)(x - 1)$

We expand to obtain,

$y + 2 = 2( {x}^{2} - 2x + 1)$

This will give us,

$y + 2 = 2 {x}^{2} - 4x + 2$

$y = {x}^{2} - 4x$

This equation is now in the form,

$y = a {x}^{2} + bx + c$
where

$a=1,b=-4,c=0$

This is the standard form

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3 years ago